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What value of xx is a solution to this equation?\newline19+x=3119 + x = 31\newlineChoices:\newline(A)x=10x = 10\newline(B)x=12x = 12

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Q. What value of xx is a solution to this equation?\newline19+x=3119 + x = 31\newlineChoices:\newline(A)x=10x = 10\newline(B)x=12x = 12
  1. Subtract 1919 from both sides: To solve for xx, we need to isolate xx on one side of the equation. We can do this by subtracting 1919 from both sides of the equation to get xx by itself.\newlineCalculation: 31−19=1231 - 19 = 12\newlinex=12x = 12

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