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What value of xx is a solution to this equation?\newline12+x=1612 + x = 16\newlineChoices:\newline(A)x=3x = 3\newline(B)x=4x = 4

Full solution

Q. What value of xx is a solution to this equation?\newline12+x=1612 + x = 16\newlineChoices:\newline(A)x=3x = 3\newline(B)x=4x = 4
  1. Start Equation Solving: Start with the given equation.\newline12+x=1612 + x = 16\newlineTo solve for xx, we need to isolate xx on one side of the equation.
  2. Subtract to Isolate x: Subtract 1212 from both sides of the equation to isolate xx.\newline12+x12=161212 + x - 12 = 16 - 12\newlineThis simplifies to:\newlinex=4x = 4
  3. Check Solution: Check the solution by substituting xx back into the original equation.12+4=1612 + 4 = 1616=1616 = 16This confirms that x=4x = 4 is the correct solution.