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What value of bb is a solution to this equation?\newlineb+16=27b + 16 = 27\newlineChoices:\newline(A)b=11b = 11\newline(B)b=12b = 12

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Full solution

Q. What value of bb is a solution to this equation?\newlineb+16=27b + 16 = 27\newlineChoices:\newline(A)b=11b = 11\newline(B)b=12b = 12
  1. Subtract to cancel: To solve for bb in the equation b+16=27b + 16 = 27, we need to isolate bb on one side of the equation. This can be done by subtracting 1616 from both sides of the equation to cancel out the +16+16 on the left side.\newlineCalculation: b+16−16=27−16b + 16 - 16 = 27 - 16
  2. Perform subtraction: Now, perform the subtraction to find the value of bb.\newlineCalculation: b=27−16b = 27 - 16
  3. Calculate final value: After calculating the subtraction, we get the value of bb.\newlineCalculation: b=11b = 11

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