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What value of bb is a solution to this equation?\newline15+b=2715 + b = 27\newlineChoices:\newline(A)b=11b = 11\newline(B)b=12b = 12

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Q. What value of bb is a solution to this equation?\newline15+b=2715 + b = 27\newlineChoices:\newline(A)b=11b = 11\newline(B)b=12b = 12
  1. Subtract 1515: Subtract 1515 from both sides to isolate bb; 15+b−15=27−1515 + b - 15 = 27 - 15

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