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What is y=13x9y=-\frac{1}{3}x-9 written in standard form?\newlineChoose 11 answer:\newline(A) x+3y=27x+3y=-27\newline(B) y=13(x+27)y=-\frac{1}{3}(x+27)\newline(C) 3y=x273y=-x-27\newline(D) 13x+y+9=0\frac{1}{3}x+y+9=0

Full solution

Q. What is y=13x9y=-\frac{1}{3}x-9 written in standard form?\newlineChoose 11 answer:\newline(A) x+3y=27x+3y=-27\newline(B) y=13(x+27)y=-\frac{1}{3}(x+27)\newline(C) 3y=x273y=-x-27\newline(D) 13x+y+9=0\frac{1}{3}x+y+9=0
  1. Rewrite equation in standard form: Rewrite the equation y=13x9y = -\frac{1}{3}x - 9 in standard form, which generally looks like Ax+By+C=0Ax + By + C = 0.
  2. Eliminate fraction by multiplication: Multiply every term by 33 to eliminate the fraction.
  3. Rearrange terms on one side: Rearrange the equation to get all terms on one side.
  4. Match with given options: Check the options given to match the derived equation.

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