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What is this series witten in sigma notation?

2.5+2.5(1.2)+2.5(1.2)^(2)+dots+2.5(1.2)^(87)
A. 
sum_(i=1)^(87)2.5(1.2)^(k)
B. 
sum_(i=1)^(8pi)2.5(1.2)^(k-1)
C. 
sum_(i=1)^(88)2.5(1.2)^(k)
D. 
sum_(i=1)^(88)2.5(1.2)^(k-1)

What is this series witten in sigma notation?\newline2.5+2.5(1.2)+2.5(1.2)2++2.5(1.2)87 2.5+2.5(1.2)+2.5(1.2)^{2}+\ldots+2.5(1.2)^{87} \newlineA. i=1872.5(1.2)k \sum_{i=1}^{87} 2.5(1.2)^{k} \newlineB. i=18π2.5(1.2)k1 \sum_{i=1}^{8 \pi} 2.5(1.2)^{k-1} \newlineC. i=1882.5(1.2)k \sum_{i=1}^{88} 2.5(1.2)^{k} \newlineD. i=1882.5(1.2)k1 \sum_{i=1}^{88} 2.5(1.2)^{k-1}

Full solution

Q. What is this series witten in sigma notation?\newline2.5+2.5(1.2)+2.5(1.2)2++2.5(1.2)87 2.5+2.5(1.2)+2.5(1.2)^{2}+\ldots+2.5(1.2)^{87} \newlineA. i=1872.5(1.2)k \sum_{i=1}^{87} 2.5(1.2)^{k} \newlineB. i=18π2.5(1.2)k1 \sum_{i=1}^{8 \pi} 2.5(1.2)^{k-1} \newlineC. i=1882.5(1.2)k \sum_{i=1}^{88} 2.5(1.2)^{k} \newlineD. i=1882.5(1.2)k1 \sum_{i=1}^{88} 2.5(1.2)^{k-1}
  1. Identify terms and ratio: Identify the first term and common ratio of the series.\newlineThe first term is 2.52.5, and the common ratio, rr, is 1.21.2 since each term is multiplied by 1.21.2 to get the next term.
  2. Write in sigma notation: Write the series in sigma notation.\newlineThe series starts at 2.52.5 and each subsequent term is the previous term multiplied by 1.21.2. The series can be written as:\newlinei=0872.5(1.2)i\sum_{i=0}^{87} 2.5 \cdot (1.2)^i
  3. Check options for match: Check the options given to match the sigma notation.\newlineOption A: i=1872.5(1.2)k\sum_{i=1}^{87} 2.5(1.2)^{k} - Incorrect because it starts from i=1i=1 and uses kk instead of ii.\newlineOption B: i=18π2.5(1.2)k1\sum_{i=1}^{8\pi} 2.5(1.2)^{k-1} - Incorrect because it uses 8π8\pi as the upper limit and k1k-1.\newlineOption C: i=1882.5(1.2)k\sum_{i=1}^{88} 2.5(1.2)^{k} - Incorrect because it starts from i=1i=1 and goes to 8888.\newlineOption D: i=1i=100 - Correct, it adjusts for the starting index of i=1i=111 by using k1k-1 and correctly goes up to 8888 terms.

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