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What is the slope of the line? $\newline$ $7x+2y=5$ $\newline$ Choose $1$ answer: $\newline$ (A) $-\frac{2}{7}$ $\newline$ (B) $\frac{7}{2}$ $\newline$ (C) $-\frac{7}{2}$ $\newline$ (D) $\frac{2}{7}$

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Operations with rational exponents

Full solution

Q. What is the slope of the line?

\newline

7x+2y=5

\newline

Choose

1

answer:

\newline

(A)

-\frac{2}{7}

\newline

(B)

\frac{7}{2}

\newline

(C)

-\frac{7}{2}

\newline

(D)

\frac{2}{7}

Rearrange and Isolate y: Step $1$ : Rearrange the equation to solve for y in terms of x. $\newline$ We start by isolating y on one side of the equation. $\newline$ Subtract $7x$ from both sides: $2y = -7x + 5$ .
Divide and Simplify: Step $2$ : Divide all terms by $2$ to solve for $y$ . $\newline$ Divide each term by $2$ : $y = (-7x + 5) / 2$ . $\newline$ This simplifies to $y = -\frac{7}{2} * x + \frac{5}{2}$ .
Identify the Slope: Step $3$ : Identify the slope from the equation $y = mx + b$ . $\newline$ In the equation $y = -\frac{7}{2} \times x + \frac{5}{2}$ , the coefficient of $x$ is the slope $(m)$ . $\newline$ So, the slope $m = -\frac{7}{2}$ .

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\newline

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\newline

1

\newline

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\newline

(B) The limit doesn't exist (probably an asymptote).

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