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What is the slope of the line?\newline4x+7=2y3-4x+7=2y-3\newlineChoose 11 answer:\newline(A) 12-\frac{1}{2}\newline(B) 13-\frac{1}{3}\newline(C) 3-3\newline(D) 2-2

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Q. What is the slope of the line?\newline4x+7=2y3-4x+7=2y-3\newlineChoose 11 answer:\newline(A) 12-\frac{1}{2}\newline(B) 13-\frac{1}{3}\newline(C) 3-3\newline(D) 2-2
  1. Rearrange equation: Rearrange the equation to solve for yy, making it easier to identify the slope. Start by adding 4x4x to both sides to isolate terms involving yy on one side. \newline4x+7+4x=2y3+4x-4x + 7 + 4x = 2y - 3 + 4x\newline7=2y3+4x7 = 2y - 3 + 4x
  2. Simplify and isolate: Next, simplify and isolate 2y2y by moving the constant term to the other side. Add 33 to both sides.\newline7+3=2y+4x7 + 3 = 2y + 4x\newline10=2y+4x10 = 2y + 4x
  3. Subtract to isolate: Now, subtract 4x4x from both sides to fully isolate the 2y2y term.\newline104x=2y10 - 4x = 2y
  4. Divide to solve: Divide every term by 22 to solve for yy.\newline(104x)/2=y(10 - 4x)/2 = y\newline52x=y5 - 2x = y
  5. Identify slope: From the equation y=52xy = 5 - 2x, identify the coefficient of xx, which represents the slope of the line.\newlineSlope = 2-2

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