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What is the slope of the line?\newline2x5y=92x-5y=9\newlineChoose 11 answer:\newline(A) 52\frac{5}{2}\newline(B) 25\frac{2}{5}\newline(C) 52-\frac{5}{2}\newline(D) 25-\frac{2}{5}

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Q. What is the slope of the line?\newline2x5y=92x-5y=9\newlineChoose 11 answer:\newline(A) 52\frac{5}{2}\newline(B) 25\frac{2}{5}\newline(C) 52-\frac{5}{2}\newline(D) 25-\frac{2}{5}
  1. Rearrange equation: Step 11: Rearrange the equation to the slope-intercept form, y=mx+by = mx + b, where mm represents the slope.\newlineStart by isolating yy on one side of the equation.\newline2x5y=92x - 5y = 9\newline5y=2x+9-5y = -2x + 9\newliney=25x95y = \frac{2}{5}x - \frac{9}{5}
  2. Identify coefficient: Step 22: Identify the coefficient of xx, which is the slope of the line.\newlineFrom the equation y=25x95y = \frac{2}{5}x - \frac{9}{5}, the coefficient of xx is 25\frac{2}{5}.

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