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What is the sign of

39(11)/(13)+(-41(1)/(13))" ? "
Choose 1 answer:
(A) Positive
(B) Negative
(c) Neither positive nor negative-the sum is zero.

What is the sign of $39 \frac{11}{13}+\left(-41 \frac{1}{13}\right) \text { ? }$ $\newline$ Choose $1$ answer: $\newline$ (A) Positive $\newline$ (B) Negative $\newline$ (C) Neither positive nor negative-the sum is zero.

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Division with rational exponents

Full solution

Q. What is the sign of

39 \frac{11}{13}+\left(-41 \frac{1}{13}\right) \text { ? }

\newline

Choose

1

answer:

\newline

(A) Positive

\newline

(B) Negative

\newline

(C) Neither positive nor negative-the sum is zero.

Calculate first term: Calculate the first term of the sum. $\newline$ The first term is $39(11)/(13)$ . To simplify this, we divide $39$ by $13$ and then multiply by $11$ . $\newline$ $39/13 = 3$ $\newline$ $3 \times 11 = 33$ $\newline$ So, the first term is $33$ .
Calculate second term: Calculate the second term of the sum. $\newline$ The second term is $-41(1)/(13)$ . To simplify this, we divide $-41$ by $13$ . $\newline$ $-41/13 = -3.15384615385$ , which can be rounded to $-3.15385$ for simplicity, but since we are only interested in the sign, we can note that the result is negative. $\newline$ So, the second term is approximately $-3.15385$ .
Add terms together: Add the two terms together. $\newline$ Now we add the first term ( $33$ ) to the second term ( $-3.15385$ ). $\newline$ $33 + (-3.15385) = 29.84615$ $\newline$ The sum is positive because $33$ is greater than $3.15385$ , and subtracting a smaller positive number from a larger positive number results in a positive number.

More problems from Division with rational exponents

Question

h(x)=\log _{2}(x)

\newline

Can we use the mean value theorem to say the equation

h^{\prime}(x)=1

has a solution where

1<x<2

\newline

1

\newline

(A) No, since the function is not differentiable on that interval.

\newline

(B) No, since the average rate of change of

h

over the interval

1 \leq x \leq 2

1

\newline

(C) Yes, both conditions for using the mean value theorem have been met.

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(C) Neither positive nor negative-the sum is zero.

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1

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(C) Neither positive nor negative-the sum is zero.

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\newline

1

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(C) Neither positive nor negative-the sum is zero.

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\newline

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\newline

(C) Neither positive nor negative-the sum is zero.

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What is the sign of

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\newline

1

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(C) Neither positive nor negative-the sum is zero.

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Question

What is the sign of

37+(-37)

\newline

1

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(C) Neither positive nor negative-the sum is zero.

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Question

\begin{array}{l} g(x)=\sqrt{2 x-9} \\ g^{\prime}(x)=? \end{array}

\newline

1

\newline

\frac{\sqrt{2 x-9}}{2}

\newline

\frac{1}{\sqrt{2 x-9}}

\newline

\frac{1}{2 \sqrt{2 x-9}}

\newline

\frac{1}{\sqrt{x}}

Posted 3 months ago

Question

-1

1

1

}{x}\sqrt{\frac{

1

1

-x}}\ln{\left(\frac{

2

2

2

1

2

2

-2

1

Posted 11 hours ago