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Let’s check out your problem:
What is the result of adding these two equations?
\newline
5
x
−
y
=
6
5 x-y=6
5
x
−
y
=
6
\newline
−
2
x
+
y
=
8
-2 x+y=8
−
2
x
+
y
=
8
\newline
□
\square
□
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Home
Math Problems
Algebra 2
Solve a system of equations using elimination
Full solution
Q.
What is the result of adding these two equations?
\newline
5
x
−
y
=
6
5 x-y=6
5
x
−
y
=
6
\newline
−
2
x
+
y
=
8
-2 x+y=8
−
2
x
+
y
=
8
\newline
□
\square
□
Write Equations:
Write down the equations to be added.
\newline
5
x
−
y
=
6
5x - y = 6
5
x
−
y
=
6
\newline
−
2
x
+
y
=
8
-2x + y = 8
−
2
x
+
y
=
8
Add Equations:
Add the equations together to combine like terms.
\newline
(
5
x
−
y
)
+
(
−
2
x
+
y
)
=
6
+
8
(5x - y) + (-2x + y) = 6 + 8
(
5
x
−
y
)
+
(
−
2
x
+
y
)
=
6
+
8
\newline
5
x
−
y
−
2
x
+
y
=
14
5x - y - 2x + y = 14
5
x
−
y
−
2
x
+
y
=
14
Combine Like Terms:
Simplify the equation by combining like terms.
\newline
5
x
−
2
x
=
3
x
5x - 2x = 3x
5
x
−
2
x
=
3
x
\newline
−
y
+
y
=
0
-y + y = 0
−
y
+
y
=
0
\newline
Therefore,
3
x
=
14
3x = 14
3
x
=
14
Final Equation:
Write the final simplified equation.
\newline
3
x
=
14
3x = 14
3
x
=
14
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