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What is the percent error for a measurement of 22 liters?\newlineIf needed, round your answer to the nearest hundredth of a percent.\newline\newline____%\_\_\_\_\%

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Q. What is the percent error for a measurement of 22 liters?\newlineIf needed, round your answer to the nearest hundredth of a percent.\newline\newline____%\_\_\_\_\%
  1. Find Error: Find the greatest possible error for 22 liters.\newlineDivide the smallest unit of measurement by 22.\newlineAssuming the smallest unit of measurement is 0.10.1 liters (since the problem does not specify), we get:\newline0.12=0.05\frac{0.1}{2} = 0.05\newlineGreatest possible error: 0.050.05 liters
  2. Calculate Percent: Calculate the percent error.\newlineWe have: \newlineMeasurement: 22 liters \newlineGreatest possible error: 0.050.05 liters \newlinePercent error = (Greatest possible error/Measurement)×100%(\text{Greatest possible error} / \text{Measurement}) \times 100\%\newlinePercent error = (0.05/2)×100%(0.05/2) \times 100\%
  3. Perform Calculation: Perform the calculation.\newlinePercent error = 0.025×100%0.025 \times 100\%\newlinePercent error = 2.5%2.5\%

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