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What is the particular solution to the differential equation 
(dy)/(dx)=(y)/(x) with the initial condition 
y(e^(2))=-1 ?

What is the particular solution to the differential equation dydx=yx \frac{d y}{d x}=\frac{y}{x} with the initial condition y(e2)=1 y\left(e^{2}\right)=-1 ?

Full solution

Q. What is the particular solution to the differential equation dydx=yx \frac{d y}{d x}=\frac{y}{x} with the initial condition y(e2)=1 y\left(e^{2}\right)=-1 ?
  1. Identify type of differential equation: Step 11: Identify the type of differential equation.\newlineWe have dydx=yx\frac{dy}{dx} = \frac{y}{x}, which is a separable differential equation.
  2. Separate variables: Step 22: Separate the variables.\newlineRearrange to get dyy=dxx\frac{dy}{y} = \frac{dx}{x}.
  3. Integrate both sides: Step 33: Integrate both sides.\newlineIntegrate dyy\frac{dy}{y} to get lny\ln|y| and integrate dxx\frac{dx}{x} to get lnx+C\ln|x| + C, where CC is the constant of integration.
  4. Solve for y: Step 44: Solve for y.\newlineExponentiate both sides to solve for y: y=elnx+C=xeCy = e^{\ln|x| + C} = |x| \cdot e^C. Let A=eCA = e^C, then y=Axy = A|x|.
  5. Apply initial condition: Step 55: Apply the initial condition to find AA. Substitute x=e2x = e^2 and y=1y = -1 into y=Axy = A|x| to get 1=Ae2-1 = A\cdot e^2.
  6. Solve for A: Step 66: Solve for A.\newlineA=1e2A = -\frac{1}{e^2}.
  7. Write particular solution: Step 77: Write the particular solution.\newlineThe particular solution is y=1e2xy = \frac{-1}{e^{2}}|x|.

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