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What is the missing constant term in the perfect square that starts with x2−12xx^2-12x?

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Full solution

Q. What is the missing constant term in the perfect square that starts with x2−12xx^2-12x?
  1. Identify values of aa and bb: Identify the values of aa and bb in the quadratic expression x2−12x+?x^2 - 12x + ?.\newlineComparing x2−12x+?x^2 - 12x + ? with ax2+bx+cax^2 + bx + c, we find:\newlinea=1a = 1\newlineb=−12b = -12\newlinec=?c = ?
  2. Determine completion value: Determine the value needed to complete the square.\newlineTo complete the square of x2−12xx^2 - 12x, we add (b/2)2(b/2)^2.\newlineCalculate (b/2)2(b/2)^2 using b=−12b = -12.\newline(−12/2)2=(−6)2(-12/2)^2 = (-6)^2
  3. Simplify calculation: Simplify the calculation to find the missing constant term.(−6)2=36(-6)^2 = 36 The missing constant term is 3636.

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