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What is the inverse of the function y=log_(3)x ?
(1) y=x^(3)
(2) y=log_(x)3
(3) y=3^(x)
(4) x=3^(y)

What is the inverse of the function y=log3x y=\log _{3} x ?\newline(A) y=x3 y=x^{3} \newline(B) y=logx3 y=\log _{x} 3 \newline(C) y=3x y=3^{x} \newline(D) x=3y x=3^{y}

Full solution

Q. What is the inverse of the function y=log3x y=\log _{3} x ?\newline(A) y=x3 y=x^{3} \newline(B) y=logx3 y=\log _{x} 3 \newline(C) y=3x y=3^{x} \newline(D) x=3y x=3^{y}
  1. Identify Function Components: Identify the original function and its components.\newlineThe original function is y=log3(x)y = \log_{3}(x), which means that 33 raised to the power of yy equals xx.
  2. Write in Exponential Form: Write the original function in exponential form.\newlineTo find the inverse, we switch xx and yy and solve for the new yy. So, we rewrite the equation as x=3yx = 3^y.
  3. Solve for Inverse Function: Solve for the new yy to express the inverse function.\newlineTo express the inverse function, we solve for yy, which gives us y=log3(x)y = \log_{3}(x). Since we have switched xx and yy, the inverse function is x=3yx = 3^{y}.
  4. Check Answer Choices: Check the answer choices to see which one matches the inverse function.\newlineThe correct answer choice that matches x=3yx = 3^y is (33) y=3(x)y = 3^{(x)}, since it represents the inverse relationship between xx and yy.

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