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What is the equation of the line that passes through the point (4,2) and has a slope of 2 ? Answer:

What is the equation of the line that passes through the point (4,2) (4,2) and has a slope of 22 ?\newlineAnswer:

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Full solution

Q. What is the equation of the line that passes through the point (4,2) (4,2) and has a slope of 22 ?\newlineAnswer:
  1. Identify slope-intercept form: Identify the slope-intercept form of a line's equation. The slope-intercept form of a line's equation is y=mx+by = mx + b, where mm is the slope and bb is the y-intercept.
  2. Find y-intercept: Use the given slope and point to find the y-intercept bb. We have the slope mm which is 22, and a point (4,2)(4,2) through which the line passes. We can use the point-slope form to find bb by plugging in the values into the slope-intercept form: y=mx+by = mx + b. 2=2(4)+b2 = 2(4) + b 2=8+b2 = 8 + b 2−8=b2 - 8 = b −6=b-6 = b
  3. Write line equation: Write the equation of the line using the slope and y-intercept.\newlineNow that we have the slope m=2m = 2 and the y-intercept b=−6b = -6, we can write the equation of the line in slope-intercept form:\newliney=2x−6y = 2x - 6

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