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What is the discriminant of the quadratic equation
-8x^(2)+8x-3=0 ?
32

-160

-32
160

What is the discriminant of the quadratic equation $-8 x^{2}+8 x-3=0$ ? $\newline$ $32$ $\newline$ $-160$ $\newline$ $-32$ $\newline$ $160$

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Division patterns with zeros

Full solution

Q. What is the discriminant of the quadratic equation

-8 x^{2}+8 x-3=0

?

\newline

32

\newline

-160

\newline

-32

\newline

160

Identify Coefficients: The discriminant of a quadratic equation in the form $ax^2 + bx + c = 0$ is given by the formula $D = b^2 - 4ac$ . We need to identify the coefficients $a$ , $b$ , and $c$ from the given equation.
Find Coefficients: In the equation $-8x^2 + 8x - 3 = 0$ , the coefficient $a$ is $-8$ , the coefficient $b$ is $8$ , and the coefficient $c$ is $-3$ .
Calculate Discriminant: Now we will calculate the discriminant using the formula $D = b^2 - 4ac$ . Substituting the values we get $D = (8)^2 - 4\cdot(-8)\cdot(-3)$ .
Substitute Values: Calculating the discriminant, we have $D = 64 - 4 \times 8 \times 3$ .
Simplify Calculation: Further simplifying, we get $D = 64 - 96$ .
Final Result: Finally, we find that $D = -32$ .

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