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What is (f−g)(x)(f - g)(x)?\newlinef(x)=−2x+1f(x) = -2x + 1\newlineg(x)=2xg(x) = 2x\newlineWrite your answer as a polynomial or a rational function in simplest form.\newline______

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Add and subtract functionsright chevron icon

Full solution

Q. What is (f−g)(x)(f - g)(x)?\newlinef(x)=−2x+1f(x) = -2x + 1\newlineg(x)=2xg(x) = 2x\newlineWrite your answer as a polynomial or a rational function in simplest form.\newline______
  1. Identify formula: Identify the formula for (f−g)(x)(f - g)(x).(f−g)(x)(f - g)(x) is the difference of f(x)f(x) and g(x)g(x).(f−g)(x)=f(x)−g(x)(f - g)(x) = f(x) - g(x)
  2. Calculate (f−g)(x)(f - g)(x): We have: \newlinef(x)=−2x+1f(x) = -2x + 1 \newlineg(x)=2xg(x) = 2x \newlineNow, calculate (f−g)(x)(f - g)(x) using the given functions.\newline(f−g)(x)=f(x)−g(x)(f - g)(x) = f(x) - g(x)\newline(f−g)(x)=(−2x+1)−(2x)(f - g)(x) = (-2x + 1) - (2x)
  3. Simplify expression: Simplify the expression by distributing the negative sign and combining like terms.\newline(f−g)(x)=−2x+1−2x(f - g)(x) = -2x + 1 - 2x\newline(f−g)(x)=−2x−2x+1(f - g)(x) = -2x - 2x + 1\newline(f−g)(x)=−4x+1(f - g)(x) = -4x + 1

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