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What could be the value of $x$ in the following equation? Select all that apply. $\newline$ $x^2 = \frac{1}{36}$ $\newline$ Multi-select Choices: $\newline$ (A) $\frac{1}{18}$ $\newline$ (B) $\sqrt{\frac{1}{36}}$ $\newline$ (C) $-\frac{1}{18}$ $\newline$ (D) $-\sqrt{\frac{1}{36}}$

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Find indefinite integrals using the substitution

Full solution

Q. What could be the value of

x

in the following equation? Select all that apply.

\newline

x^2 = \frac{1}{36}

\newline

Multi-select Choices:

\newline

(A)

\frac{1}{18}

\newline

(B)

\sqrt{\frac{1}{36}}

\newline

(C)

-\frac{1}{18}

\newline

(D)

-\sqrt{\frac{1}{36}}

Solve for x: Step $1$ : Solve for x by taking the square root of both sides. $\newline$ $x = \pm\sqrt{\frac{1}{36}}$ $\newline$ Calculation: $\sqrt{\frac{1}{36}} = \frac{1}{6}$ $\newline$ So, $x = \pm\frac{1}{6}$
Check possible values: Step $2$ : Check the possible values of $x$ against the multi-select choices. $\newline$ $x = \frac{1}{6}$ matches (A) $\frac{1}{18}$ ? No $\newline$ $x = \frac{1}{6}$ matches (B) $\sqrt{\frac{1}{36}}$ ? No $\newline$ $x = \frac{1}{6}$ matches (C) $-\frac{1}{18}$ ? No $\newline$ $x = \frac{1}{6}$ matches (D) $-\sqrt{\frac{1}{36}}$ ? No $\newline$ $x = -\frac{1}{6}$ matches (A) $\frac{1}{18}$ ? No $\newline$ $x = -\frac{1}{6}$ matches (B) $\sqrt{\frac{1}{36}}$ ? No $\newline$ $x = -\frac{1}{6}$ matches (C) $-\frac{1}{18}$ ? Yes $\newline$ $x = -\frac{1}{6}$ matches (D) $-\sqrt{\frac{1}{36}}$ ? No

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