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What are the foci of the hyperbola represented by the equation 
(x^(2))/(5)-(y^(2))/(7)=1?
Choose 1 answer:
(A) 
(0,sqrt12) and 
(0,-sqrt12)
(B) 
(sqrt12,0) and 
(-sqrt12,0)
(c) 
(sqrt74,0) and 
(-sqrt74,0)
(D) 
(0,sqrt74) and 
(0,-sqrt74)

What are the foci of the hyperbola represented by the equation x25y27=1? \frac{x^{2}}{5}-\frac{y^{2}}{7}=1 ? \newlineChoose 11 answer:\newline(A) (0,12) (0, \sqrt{12}) and (0,12) (0,-\sqrt{12}) \newline(B) (12,0) (\sqrt{12}, 0) and (12,0) (-\sqrt{12}, 0) \newline(C) (74,0) (\sqrt{74}, 0) and (74,0) (-\sqrt{74}, 0) \newline(D) (0,74) (0, \sqrt{74}) and (0,74) (0,-\sqrt{74})

Full solution

Q. What are the foci of the hyperbola represented by the equation x25y27=1? \frac{x^{2}}{5}-\frac{y^{2}}{7}=1 ? \newlineChoose 11 answer:\newline(A) (0,12) (0, \sqrt{12}) and (0,12) (0,-\sqrt{12}) \newline(B) (12,0) (\sqrt{12}, 0) and (12,0) (-\sqrt{12}, 0) \newline(C) (74,0) (\sqrt{74}, 0) and (74,0) (-\sqrt{74}, 0) \newline(D) (0,74) (0, \sqrt{74}) and (0,74) (0,-\sqrt{74})
  1. Equation form of hyperbola: The given equation is in the form of a hyperbola with the equation (x2a2)(y2b2)=1(\frac{x^2}{a^2}) - (\frac{y^2}{b^2}) = 1, where a2a^2 is under the x2x^2 term and b2b^2 is under the y2y^2 term. For a hyperbola of this form, the foci are located at (±c,0)(\pm c, 0) if the x2x^2 term is positive, and at (0,±c)(0, \pm c) if the y2y^2 term is positive, where cc is the distance from the center to each focus.
  2. Identifying a2a^2 and b2b^2: We identify a2a^2 and b2b^2 from the given equation. Here, a2=5a^2 = 5 and b2=7b^2 = 7. The next step is to find the value of cc, which is calculated using the formula c2=a2+b2c^2 = a^2 + b^2 for hyperbolas.
  3. Calculating the value of c: We calculate c2c^2 using the values of a2a^2 and b2b^2: c2=5+7=12c^2 = 5 + 7 = 12. Therefore, c=12c = \sqrt{12}.
  4. Locating the foci: Since the x2x^2 term is positive and comes first in the equation, the foci are located along the x-axis. Thus, the coordinates of the foci are (±12,0)(\pm\sqrt{12}, 0).
  5. Matching the result with choices: We match our result with the given choices. The correct choice is (B) (12,0)(\sqrt{12},0) and (12,0)(-\sqrt{12},0).

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