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what are the attachments and origins of biceps brachialis

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Find the length of the transverse or conjugate axes of a hyperbolaright chevron icon

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Q. what are the attachments and origins of biceps brachialis
  1. Identify orientation: Identify the orientation of the hyperbola. x264−y236=1\frac{x^2}{64} - \frac{y^2}{36} = 1 Since the x2x^2 term is positive and comes first, it's a horizontal hyperbola.
  2. Compare with standard form: Compare the given equation with the standard form of a horizontal hyperbola equation. \newline(x2a2−y2b2=1)(\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1)\newlineHere, a2=64a^2 = 64, so a=8a = 8.
  3. Calculate transverse axis length: Calculate the length of the transverse axis.\newlineLength of transverse axis =2a= 2a\newline=2×8= 2 \times 8\newline=16= 16

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