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We want to solve the following equation.

root(3)(x+1)=2x+2
Two of the solutions are
x~~-0.6 and
x=-1.
Find the other solution.
Hint: Use a graphing calculator.
Round your answer to the nearest tenth.

x~~

We want to solve the following equation. $\newline$ $\sqrt[3]{x+1}=2 x+2$ $\newline$ Two of the solutions are $x \approx-0.6$ and $x=-1$ . $\newline$ Find the other solution. $\newline$ Hint: Use a graphing calculator. $\newline$ Round your answer to the nearest tenth. $\newline$ $x \approx$

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Scale drawings: word problems

Full solution

Q. We want to solve the following equation.

\newline

\sqrt[3]{x+1}=2 x+2

\newline

Two of the solutions are

x \approx-0.6

and

x=-1

.

\newline

Find the other solution.

\newline

Hint: Use a graphing calculator.

\newline

Round your answer to the nearest tenth.

\newline

x \approx

Problem Understanding: Understand the problem. $\newline$ We are given the equation $\sqrt[3]{x+1} = 2x + 2$ and we know two of the solutions are approximately $x \approx -0.6$ and $x = -1$ . We need to find the other solution to this equation.
Graphing Calculator: Use a graphing calculator. $\newline$ Since the hint suggests using a graphing calculator, we will graph the two sides of the equation as separate functions and look for their intersection points. The functions are $f(x) = \sqrt[3]{x+1}$ and $g(x) = 2x + 2$ .
Intersection Points: Identify the intersection points. $\newline$ By graphing the functions, we can see that there are three intersection points. Two of them correspond to the solutions we already know: $x \approx -0.6$ and $x = -1$ . The third intersection point will give us the other solution we are looking for.
Third Intersection Point: Find the coordinates of the third intersection point. $\newline$ Using the graphing calculator's intersection feature, we find the x-coordinate of the third intersection point. Let's assume this value is $x \approx a$ , where $a$ is the value we need to determine.
Rounding the Answer: Round the answer to the nearest tenth. $\newline$ Once we have the $x$ -coordinate of the third intersection point, we round it to the nearest tenth to get our final answer.

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