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We want to find the zeros of this polynomial:

p(x)=x(2x+3)(x-1)(x+2)
Plot all the zeros ( 
x-intercepts) of the polynomial in the interactive graph.

We want to find the zeros of this polynomial:\newlinep(x)=x(2x+3)(x1)(x+2) p(x)=x(2 x+3)(x-1)(x+2) \newlinePlot all the zeros ( x x -intercepts) of the polynomial in the interactive graph.

Full solution

Q. We want to find the zeros of this polynomial:\newlinep(x)=x(2x+3)(x1)(x+2) p(x)=x(2 x+3)(x-1)(x+2) \newlinePlot all the zeros ( x x -intercepts) of the polynomial in the interactive graph.
  1. Set Polynomial Equal to Zero: step_1: Set the polynomial equal to zero and solve for xx.p(x)=x(2x+3)(x1)(x+2)=0p(x) = x(2x + 3)(x - 1)(x + 2) = 0
  2. Solve Each Factor: step2_2: Solve each factor set to zero.\newlinex=0x = 0,\newline2x+3=02x + 3 = 0,\newlinex1=0x - 1 = 0,\newlinex+2=0x + 2 = 0
  3. Solve for x: step_3: Solve for x in each equation.\newlinex=0x = 0,\newline2x+3=02x=3x=322x + 3 = 0 \rightarrow 2x = -3 \rightarrow x = -\frac{3}{2},\newlinex1=0x=1x - 1 = 0 \rightarrow x = 1,\newlinex+2=0x=2x + 2 = 0 \rightarrow x = -2

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