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Let’s check out your problem:
We want to find the zeros of this polynomial:
\newline
p
(
x
)
=
x
(
2
x
+
3
)
(
x
−
1
)
(
x
+
2
)
p(x)=x(2 x+3)(x-1)(x+2)
p
(
x
)
=
x
(
2
x
+
3
)
(
x
−
1
)
(
x
+
2
)
\newline
Plot all the zeros (
x
x
x
-intercepts) of the polynomial in the interactive graph.
View step-by-step help
Home
Math Problems
Algebra 2
Write a polynomial from its roots
Full solution
Q.
We want to find the zeros of this polynomial:
\newline
p
(
x
)
=
x
(
2
x
+
3
)
(
x
−
1
)
(
x
+
2
)
p(x)=x(2 x+3)(x-1)(x+2)
p
(
x
)
=
x
(
2
x
+
3
)
(
x
−
1
)
(
x
+
2
)
\newline
Plot all the zeros (
x
x
x
-intercepts) of the polynomial in the interactive graph.
Set Polynomial Equal to Zero:
step_1: Set the polynomial equal to zero and solve for
x
x
x
.
p
(
x
)
=
x
(
2
x
+
3
)
(
x
−
1
)
(
x
+
2
)
=
0
p(x) = x(2x + 3)(x - 1)(x + 2) = 0
p
(
x
)
=
x
(
2
x
+
3
)
(
x
−
1
)
(
x
+
2
)
=
0
Solve Each Factor:
step
2
_2
2
: Solve each factor set to zero.
\newline
x
=
0
x = 0
x
=
0
,
\newline
2
x
+
3
=
0
2x + 3 = 0
2
x
+
3
=
0
,
\newline
x
−
1
=
0
x - 1 = 0
x
−
1
=
0
,
\newline
x
+
2
=
0
x + 2 = 0
x
+
2
=
0
Solve for x:
step_3: Solve for x in each equation.
\newline
x
=
0
x = 0
x
=
0
,
\newline
2
x
+
3
=
0
→
2
x
=
−
3
→
x
=
−
3
2
2x + 3 = 0 \rightarrow 2x = -3 \rightarrow x = -\frac{3}{2}
2
x
+
3
=
0
→
2
x
=
−
3
→
x
=
−
2
3
,
\newline
x
−
1
=
0
→
x
=
1
x - 1 = 0 \rightarrow x = 1
x
−
1
=
0
→
x
=
1
,
\newline
x
+
2
=
0
→
x
=
−
2
x + 2 = 0 \rightarrow x = -2
x
+
2
=
0
→
x
=
−
2
More problems from Write a polynomial from its roots
Question
Find the solutions of the quadratic equation
2
x
2
−
8
x
−
9
=
0
2 x^{2}-8 x-9=0
2
x
2
−
8
x
−
9
=
0
.
\newline
Choose
1
1
1
answer:
\newline
(A)
2
±
34
2
i
2 \pm \frac{\sqrt{34}}{2} i
2
±
2
34
i
\newline
(B)
−
2
±
34
2
i
-2 \pm \frac{\sqrt{34}}{2} i
−
2
±
2
34
i
\newline
(C)
2
±
34
2
2 \pm \frac{\sqrt{34}}{2}
2
±
2
34
\newline
(D)
1
±
34
4
1 \pm \frac{\sqrt{34}}{4}
1
±
4
34
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Posted 3 months ago
Question
x
3
+
7
x
2
−
36
x^{3}+7 x^{2}-36
x
3
+
7
x
2
−
36
\newline
The polynomial has zeros at
−
6
-6
−
6
and
2
2
2
. If the remaining zero is
z
z
z
, then what is the value of
−
z
-z
−
z
?
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Posted 3 months ago
Question
Solve for
x
x
x
.
\newline
Enter the solutions from least to greatest.
\newline
(
−
5
x
+
4
)
(
x
−
3
)
=
0
lesser
x
=
□
greater
x
=
□
\begin{array}{l} (-5 x+4)(x-3)=0 \\ \text { lesser } x=\square \\ \text { greater } x=\square \end{array}
(
−
5
x
+
4
)
(
x
−
3
)
=
0
lesser
x
=
□
greater
x
=
□
Get tutor help
Posted 3 months ago
Question
Solve for
x
x
x
.
\newline
Enter the solutions from least to greatest.
\newline
(
2
x
+
4
)
(
3
x
−
2
)
=
0
(2 x+4)(3 x-2)=0
(
2
x
+
4
)
(
3
x
−
2
)
=
0
\newline
lesser
x
=
x=
x
=
\newline
greater
x
=
x=
x
=
Get tutor help
Posted 3 months ago
Question
Solve for
x
x
x
.
\newline
Enter the solutions from least to greatest.
\newline
(
3
x
−
6
)
(
−
x
+
3
)
=
0
lesser
x
=
□
greater
x
=
□
\begin{array}{l} (3 x-6)(-x+3)=0 \\ \text { lesser } x=\square \\ \text { greater } x=\square \end{array}
(
3
x
−
6
)
(
−
x
+
3
)
=
0
lesser
x
=
□
greater
x
=
□
Get tutor help
Posted 3 months ago
Question
Solve for
x
x
x
.
\newline
Enter the solutions from least to greatest.
\newline
(
x
+
6
)
(
−
x
+
1
)
=
0
(x+6)(-x+1)=0
(
x
+
6
)
(
−
x
+
1
)
=
0
\newline
lesser
x
=
x=
x
=
\newline
greater
x
=
x=
x
=
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Posted 3 months ago
Question
Is the following function even, odd, or neither?
\newline
f
(
x
)
=
3
x
2
+
2
f(x)=\frac{3}{x^{2}+2}
f
(
x
)
=
x
2
+
2
3
\newline
Choose
1
1
1
answer:
\newline
(A) Even
\newline
(B) Odd
\newline
(C) Neither
Get tutor help
Posted 3 months ago
Question
Is the following function even, odd, or neither?
\newline
f
(
x
)
=
1
4
−
x
2
f(x)=\frac{1}{4-x^{2}}
f
(
x
)
=
4
−
x
2
1
\newline
Choose
1
1
1
answer:
\newline
(A) Even
\newline
(B) Odd
\newline
(C) Neither
Get tutor help
Posted 3 months ago
Question
Is the following function even, odd, or neither?
\newline
f
(
x
)
=
2
∣
x
∣
−
5
f(x)=2|x|-5
f
(
x
)
=
2∣
x
∣
−
5
\newline
Choose
1
1
1
answer:
\newline
(A) Even
\newline
(B) Odd
\newline
(C) Neither
Get tutor help
Posted 3 months ago
Question
Is the following function even, odd, or neither?
\newline
f
(
x
)
=
x
x
2
+
1
f(x)=\frac{x}{x^{2}+1}
f
(
x
)
=
x
2
+
1
x
\newline
Choose
1
1
1
answer:
\newline
(A) Even
\newline
(B) Odd
\newline
(C) Neither
Get tutor help
Posted 3 months ago