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A cylinder has a base diameter of 6 feet and a height of 18 feet. What is its volume in cubic feet, to the nearest tenths place?V=_____feet^3

A cylinder has a base diameter of $6$ feet and a height of $18$ feet. What is its volume in cubic feet, to the nearest tenths place? $\newline$ V=____ feet ${ }^{3}$ $\newline$

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Volume of cubes and rectangular prisms: word problems

Full solution

Q. A cylinder has a base diameter of

6

feet and a height of

18

feet. What is its volume in cubic feet, to the nearest tenths place?

\newline

V=____ feet

{ }^{3}

\newline

Identify Formula: Identify the formula for the volume of a cylinder. $\newline$ The formula for the volume of a cylinder is $V = \pi r^2 h$ , where $r$ is the radius of the base and $h$ is the height of the cylinder.
Calculate Radius: Calculate the radius of the base of the cylinder. $\newline$ The diameter of the base is given as $6$ feet. The radius is half of the diameter, so the radius $r = \frac{\text{diameter}}{2} = \frac{6\ \text{feet}}{2} = 3$ feet.
Substitute Values: Substitute the radius and height into the volume formula. $\newline$ Using the radius of $3$ feet and the height of $18$ feet, the volume $V = \pi \times (3 \text{ feet})^2 \times 18 \text{ feet}.$
Calculate Volume: Calculate the volume. $\newline$ $V = \pi \times 3^2 \times 18$ $\newline$ $V = \pi \times 9 \times 18$ $\newline$ $V = \pi \times 162$ $\newline$ To find the volume to the nearest tenths place, we use the value of $\pi$ as approximately $3.14159$ . $\newline$ $V \approx 3.14159 \times 162$ $\newline$ $V \approx 508.93878$ cubic feet
Round Volume: Round the volume to the nearest tenths place. The volume, rounded to the nearest tenths place, is approximately $508.9$ cubic feet.

More problems from Volume of cubes and rectangular prisms: word problems

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\newline

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\newline

1

\newline

h=4\cdot0.79^{(b-1)}

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