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Vijay is building a new rectangular enclosure in his backyard for his chickens. He has 40 feet of fencing material and he wants the width of the enclosure to be 8 feet. If 
l is the length of the enclosure, and Vijay uses all of the fencing material, which equation best models the situation?
Choose 1 answer:
(A) 
l+8=40
(B) 
2l+8=40
(c) 
2(l+8)=40
(D) 
2l+2(l+8)=40

Vijay is building a new rectangular enclosure in his backyard for his chickens. He has 4040 feet of fencing material and he wants the width of the enclosure to be 88 feet. If l l is the length of the enclosure, and Vijay uses all of the fencing material, which equation best models the situation?\newlineChoose 11 answer:\newline(A) l+8=40 l+8=40 \newline(B) 2l+8=40 2 l+8=40 \newline(c) 2(l+8)=40 2(l+8)=40 \newline(D) 2l+2(l+8)=40 2 l+2(l+8)=40

Full solution

Q. Vijay is building a new rectangular enclosure in his backyard for his chickens. He has 4040 feet of fencing material and he wants the width of the enclosure to be 88 feet. If l l is the length of the enclosure, and Vijay uses all of the fencing material, which equation best models the situation?\newlineChoose 11 answer:\newline(A) l+8=40 l+8=40 \newline(B) 2l+8=40 2 l+8=40 \newline(c) 2(l+8)=40 2(l+8)=40 \newline(D) 2l+2(l+8)=40 2 l+2(l+8)=40
  1. Identify Total Fencing Material: Identify the total amount of fencing material and the given width. Calculate the perimeter needed using the formula for the perimeter of a rectangle, P=2(length+width)P = 2(\text{length} + \text{width}). Here, the total fencing material is 4040 feet, and the width is 88 feet.
  2. Calculate Perimeter Using Formula: Substitute the known values into the perimeter formula to find the equation for the length. Since the perimeter is 4040 feet and the width is 88 feet, the equation becomes 2(l+8)=402(l + 8) = 40.
  3. Substitute Values into Equation: Check if the equation 2(l+8)=402(l + 8) = 40 correctly represents the situation where the total perimeter is used up by the length and twice the width. This equation accounts for both lengths and both widths, matching the problem's conditions.