Resources

Resources

Bytelearn - cat image with glasses

AI tutor

Welcome to Bytelearn!

Let’s check out your problem:

$V= \frac{4}{3} \pi (3)^3$

View step-by-step help

View step-by-step help

Powers with decimal bases

Full solution

Q.

V= \frac{4}{3} \pi (3)^3

Plug Radius into Formula: We're given the formula for the volume of a sphere, $V = \frac{4}{3} \pi r^3$ . Plug in the radius ( $r = 3$ ) into the formula. $\newline$ $V = \frac{4}{3} \pi (3)^3$
Calculate Exponent: Calculate the exponent part first, $(3)^3$ means $3 \times 3 \times 3$ . $3^3 = 27$
Multiply by $\pi$ : Now, multiply the result by $\pi$ . $27 \times \pi = 27\pi$
Multiply by Fraction: Finally, multiply by the fraction $\frac{4}{3}$ . $\newline$ $V = \frac{4}{3} \times 27\pi$
Final Calculation: Do the multiplication: $\frac{4}{3}$ of $27$ is the same as $4$ times $27$ divided by $3$ . $\newline$ $4 \times 27 = 108$ $\newline$ $108 / 3 = 36$ $\newline$ $V = 36\pi$

More problems from Powers with decimal bases

Question

Write the expression using an exponent.

\newline

2 \times 2

\newline

Posted 2 months ago

Question

Evaluate the expression.

4 - 4^2

Posted 2 months ago

Question

x^2 = 4

Posted 1 month ago

Question

x^2 = 9

Posted 3 months ago

Question

\newline

x^2 = 0

\newline

Write your answer in simplified, rationalized form.

\newline

x =

x =

Posted 3 months ago

Question

x

\newline

8 = 2^x

\newline

x =

Posted 3 months ago

Question

x

\newline

6 = 7^x

\newline

x =

Posted 3 months ago

Question

Select the equivalent expression.

\newline

((8^{-5})/(2^{-2}))^{-4}=?

\newline

1

\newline

\newline

(8^{20})/(2^{8})

\newline

\newline

(2^{6})/(8^{9})

\newline

\newline

(1)/(8\cdot 2^{2})

Posted 4 days ago

Question

Select the equivalent expression.

\newline

\left(\frac{b^{7}}{4^{5}}\right)^{-3}=\,?

\newline

1

\newline

\frac{b^{21}}{4^{15}}

\newline

\frac{4^{15}}{b^{21}}

\newline

b^{-21}\cdot 4^{-15}

Posted 1 month ago

Question

Select the equivalent expression.

\newline

(3^{3}\cdot6^{6})^{-3}=

\newline

1

\newline

\frac{1}{3^{9}\cdot6^{18}}

\newline

\frac{6^{18}}{3^{9}}

\newline

\frac{3^{9}}{6^{18}}

Posted 1 month ago