Resourcesdown chevron
Testimonials
Plans
Sign in
Sign up
Resourcesright arrow
Testimonials
Plans
Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Utilizar la calculadora gráfica de ALEKS para resolver el sistema de ecuaciones. {:[6-0.9 x=0.4 y],[-y+0.2 x=3.6]:} Redondear a la centésima más cercana. (x,y)=(◻,◻)

Utilizar la calculadora gráfica de ALEKS para resolver el sistema de ecuaciones.\newline6−0.9x=0.4y−y+0.2x=3.6 \begin{array}{l} 6-0.9 x=0.4 y \\ -y+0.2 x=3.6 \end{array} \newlineRedondear a la centésima más cercana.\newline(x,y)=(□,□) (x, y)=(\square, \square)

View step-by-step helpView step-by-step help
Homeright chevron icon
Math Problemsright chevron icon
Algebra 2right chevron icon
Domain and range of absolute value functions: equationsright chevron icon

Full solution

Q. Utilizar la calculadora gráfica de ALEKS para resolver el sistema de ecuaciones.\newline6−0.9x=0.4y−y+0.2x=3.6 \begin{array}{l} 6-0.9 x=0.4 y \\ -y+0.2 x=3.6 \end{array} \newlineRedondear a la centésima más cercana.\newline(x,y)=(□,□) (x, y)=(\square, \square)
  1. Write System of Equations: Write down the system of equations.\newlineWe have the following system of equations:\newline6−0.9x=0.4y6 - 0.9x = 0.4y\newline−y+0.2x=3.6-y + 0.2x = 3.6
  2. Solve for y: Solve the first equation for y.\newlineTo find yy in terms of xx, we can rearrange the first equation:\newline0.4y=6−0.9x0.4y = 6 - 0.9x\newliney=(6−0.9x)/0.4y = (6 - 0.9x) / 0.4\newliney=15−(0.9x/0.4)y = 15 - (0.9x / 0.4)\newliney=15−2.25xy = 15 - 2.25x
  3. Substitute into Second Equation: Substitute the expression for yy into the second equation.\newlineNow we substitute y=15−2.25xy = 15 - 2.25x into the second equation:\newline−(15−2.25x)+0.2x=3.6-\left(15 - 2.25x\right) + 0.2x = 3.6\newline−15+2.25x+0.2x=3.6-15 + 2.25x + 0.2x = 3.6\newline2.25x+0.2x=3.6+152.25x + 0.2x = 3.6 + 15\newline2.45x=18.62.45x = 18.6
  4. Solve for x: Solve for x.\newlineDivide both sides by 2.452.45 to find xx:\newlinex=18.62.45x = \frac{18.6}{2.45}\newlinex=7.59x = 7.59 (rounded to the nearest hundredth)
  5. Substitute for y: Substitute the value of xx back into the expression for yy.\newlineNow that we have xx, we can find yy:\newliney=15−2.25(7.59)y = 15 - 2.25(7.59)\newliney=15−17.0775y = 15 - 17.0775\newliney=−2.08y = -2.08 (rounded to the nearest hundredth)

More problems from Domain and range of absolute value functions: equations

Question
What is the domain of this function?\newline(9,–2)(6,–10)(–3,9)(5,2)(9,–2)(6,–10)(–3,9)(5,2)\newlineChoices:\newline(A){–3,5,6,9}(B){–10,–2,2,9}(C){2,5,6,9}(D){–6,–3,5,9}(A)\{–3,5,6,9\}\newline(B)\{–10,–2,2,9\}\newline(C)\{2,5,6,9\}\newline(D)\{–6,–3,5,9\}
Get tutor helpright-arrow

Posted 2 months ago

Question
Look at this set of ordered pairs:\newline(2,14)(2, 14)\newline(10,12)(10, 12)\newline(3,−19)(3, -19)\newlineIs this relation a function?\newlineChoices:\newline[[yes]\text{[[yes]}[no]]\text{[no]]}
Get tutor helpright-arrow

Posted 2 months ago

Question
Use the following function rule to find f(11) f(11) .\newlinef(x)=−10−7x f(x) = -10 - 7x \newlinef(11)= f(11) = _____
Get tutor helpright-arrow

Posted 2 months ago

Question
Find the slope of the line y=−3x−25 y = -3x - \frac{2}{5} .\newlineSimplify your answer and write it as a proper fraction, improper fraction, or integer.\newline_____\_\_\_\_\_
Get tutor helpright-arrow

Posted 2 months ago

Question
A line has a slope of 33 and passes through the point (−2,−10)(-2,-10). Write its equation in slope-intercept form.\newlineWrite your answer using integers, proper fractions, and improper fractions in simplest form.
Get tutor helpright-arrow

Posted 2 months ago

Question
What is the range of this function?\newliney = |x|\newlineChoices:\newlineall real numbers\text{all real numbers}\newline{y∣y≥0}\{y \mid y \geq 0\}\newline{y∣y≤0}\{y \mid y \leq 0\}\newline{y∣y>0}\{y \mid y > 0\}
Get tutor helpright-arrow

Posted 3 months ago

Question
Find g(x) g(x) , where g(x) g(x) is the translation 1 1 unit down of f(x)=∣x∣ f(x) = |x| .\newlineWrite your answer in the form a∣x−h∣+k a|x - h| + k , where a a , h h , and k k are integers.\newlineg(x)= g(x) = ______\newline
Get tutor helpright-arrow

Posted 3 months ago

Question
What is the domain of this function?\newline(8,–1)(7,–11)(–4,10)(4,3)(8,–1)(7,–11)(–4,10)(4,3)\newlineChoices: \newline(A){–4,4,7,8}(A)\{–4,4,7,8\}\newline(B){–11,–1,3,10}(B)\{–11,–1,3,10\}\newline(C){3,4,7,8}(C)\{3,4,7,8\}\newline(D){–7,–4,4,8}(D)\{–7,–4,4,8\}
Get tutor helpright-arrow

Posted 4 months ago

Question
What is the domain of this function?\newline(10, –3)(2, –9)(–5, 8)(3, 1)(10,\,–3)(2,\,–9)(–5,\,8)(3,\,1)\newlineChoices:\newline[{–5,2,3,10}][{–9, –3,1,8}][{1,2,3,10}][{–10, –5,2,3}][\{–5,2,3,10\}][\{–9,\,–3,1,8\}][\{1,2,3,10\}][\{–10,\,–5,2,3\}]
Get tutor helpright-arrow

Posted 2 months ago

Question
What is the domain of this function?\newline(1,–4)(9,–12)(–6,11)(7,5)(1,–4)(9,–12)(–6,11)(7,5)\newlineChoices:(A){–6,1,7,9}\newline\\(A)\{–6,1,7,9\}\newline(B){–12,–4,5,11}(B)\{–12,–4,5,11\}\newline(C{5,1,7,9}(C\{5,1,7,9\}\newline(D){–9,–6,1,7}(D)\{–9,–6,1,7\}
Get tutor helpright-arrow

Posted 2 months ago

View all (44)