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Use the values 
log 48~~1.68 and 
log 3~~0.48 to find the approximate value of 
log_(3)48.

log_(3)48~~

Use the values log481.68 \log 48 \approx 1.68 and log30.48 \log 3 \approx 0.48 to find the approximate value of log348 \log _{3} 48 .\newlinelog348 \log _{3} 48 \approx

Full solution

Q. Use the values log481.68 \log 48 \approx 1.68 and log30.48 \log 3 \approx 0.48 to find the approximate value of log348 \log _{3} 48 .\newlinelog348 \log _{3} 48 \approx
  1. Apply change of base formula: Use the change of base formula: log348=log(48)log(3)\log_{3}48 = \frac{\log(48)}{\log(3)}.
  2. Substitute values: Plug in the given values: log3481.680.48\log_{3}48 \approx \frac{1.68}{0.48}.
  3. Perform division: Perform the division: 1.68/0.483.51.68 / 0.48 \approx 3.5.

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