Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

USE THE TABLE BELOW TO HELP YOU FIND THE SURFACE AREA OF THE FIGURE BELOW. DRAG AND DROP THE MATCHING PIECE TO THE WHITE RECTANGLES.





SHAPE 1
SHAPE 2
SHAPE 3


FORMULA


A=(b*h)/(2)






PLUG IN


VALUES







A=(5*7)/(2)


AREA
28 inches 
^(2)






TOTAL SURFACE AREA

◻

[A=(b*h)/(2),A=(4*4)/(2),A=(5*7)/(2)],[A=b*h,A=4*7,A=(5*4)/(2)]]
35 in 
^(2)

A=(5*4)/(2)

17.5in^(2)
16 in 
^(2)

A=4*7
8 in 
^(2)

A=b*h

A=4*7quad A=(5)/(2)
Notes

USE THE TABLE BELOW TO HELP YOU FIND THE SURFACE AREA OF THE FIGURE BELOW. DRAG AND DROP THE MATCHING PIECE TO THE WHITE RECTANGLES.\newline\begin{tabular}{|c|c|c|c|}\newline\hline & SHAPE 11 & SHAPE 22 & SHAPE 33 \\\newline\hline FORMULA & & A=bh2 A=\frac{b \cdot h}{2} & \\\newline\hline \begin{tabular}{l} \newlinePLUG IN \\\newlineVALUES\newline\end{tabular} & & & A=572 A=\frac{5 \cdot 7}{2} \\\newline\hline AREA & 2828 inches 2 ^{2} & & \\\newline\hline\newline\end{tabular}\newlineTOTAL SURFACE AREA\newline \square \newlineA=bh2A=442A=572A=bhA=47A=542 \begin{array}{l|l|l|} A=\frac{b \cdot h}{2} & A=\frac{4 \cdot 4}{2} & A=\frac{5 \cdot 7}{2} \\ \hdashline A=b \cdot h & A=4 \cdot 7 & A=\frac{5 \cdot 4}{2} \end{array} \newline3535 in 2 ^{2} \newlineA=542 A=\frac{5 \cdot 4}{2} \newline17.5in2 17.5 \mathrm{in}^{2} \newline1616 in 2 ^{2} \newlineA=47 A=4 \cdot 7 \newline88 in 2 ^{2} \newlineA=572 A=\frac{5 \cdot 7}{2} 00\newlineA=572 A=\frac{5 \cdot 7}{2} 11\newlineNotes

Full solution

Q. USE THE TABLE BELOW TO HELP YOU FIND THE SURFACE AREA OF THE FIGURE BELOW. DRAG AND DROP THE MATCHING PIECE TO THE WHITE RECTANGLES.\newline\begin{tabular}{|c|c|c|c|}\newline\hline & SHAPE 11 & SHAPE 22 & SHAPE 33 \\\newline\hline FORMULA & & A=bh2 A=\frac{b \cdot h}{2} & \\\newline\hline \begin{tabular}{l} \newlinePLUG IN \\\newlineVALUES\newline\end{tabular} & & & A=572 A=\frac{5 \cdot 7}{2} \\\newline\hline AREA & 2828 inches 2 ^{2} & & \\\newline\hline\newline\end{tabular}\newlineTOTAL SURFACE AREA\newline \square \newlineA=bh2A=442A=572A=bhA=47A=542 \begin{array}{l|l|l|} A=\frac{b \cdot h}{2} & A=\frac{4 \cdot 4}{2} & A=\frac{5 \cdot 7}{2} \\ \hdashline A=b \cdot h & A=4 \cdot 7 & A=\frac{5 \cdot 4}{2} \end{array} \newline3535 in 2 ^{2} \newlineA=542 A=\frac{5 \cdot 4}{2} \newline17.5in2 17.5 \mathrm{in}^{2} \newline1616 in 2 ^{2} \newlineA=47 A=4 \cdot 7 \newline88 in 2 ^{2} \newlineA=572 A=\frac{5 \cdot 7}{2} 00\newlineA=572 A=\frac{5 \cdot 7}{2} 11\newlineNotes
  1. Calculate Area of SHAPE 11: First, let's calculate the area of SHAPE 11 using the formula A=b×h2A=\frac{b\times h}{2}. Plugging in the values, we get A=5×72A=\frac{5\times 7}{2}.
  2. Math for SHAPE 11: Now, do the math for SHAPE 11: A=5×72=352=17.5A=\frac{5\times7}{2} = \frac{35}{2} = 17.5 inches squared.
  3. Calculate Area of SHAPE 22: Next, let's calculate the area of SHAPE 22 using the formula A=b×hA=b\times h. Plugging in the values, we get A=4×7A=4\times 7.
  4. Math for SHAPE 22: Now, do the math for SHAPE 22: A=4×7=28A=4\times7 = 28 inches squared.
  5. Calculate Area of SHAPE 33: Finally, let's calculate the area of SHAPE 33 using the formula A=b×h2A=\frac{b\times h}{2}. Plugging in the values, we get A=5×42A=\frac{5\times 4}{2}.
  6. Math for SHAPE 33: Now, do the math for SHAPE 33: A=(5×4)/2=20/2=10A=(5\times4)/2 = 20/2 = 10 inches squared. Oops, looks like I made a mistake here, it should be 1010 inches squared, not 17.517.5 inches squared.