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Use the shell method to find the volume of the solid generated by revolving the shaded region about the 
x-axis.
Set up the integral that gives the volume of the solid.
The volume of the solid generated by revolving the shaded region about the 
x-axis is 
◻ cubic units. (Type an exact answer, using 
pi as needed.)

Use the shell method to find the volume of the solid generated by revolving the shaded region about the x x -axis.\newlineSet up the integral that gives the volume of the solid.\newlineThe volume of the solid generated by revolving the shaded region about the x x -axis is \square cubic units. (Type an exact answer, using π \pi as needed.)

Full solution

Q. Use the shell method to find the volume of the solid generated by revolving the shaded region about the x x -axis.\newlineSet up the integral that gives the volume of the solid.\newlineThe volume of the solid generated by revolving the shaded region about the x x -axis is \square cubic units. (Type an exact answer, using π \pi as needed.)
  1. Identify function & limits: Identify the function and limits for the shaded region. Assume the function is y=x2y = x^2 from x=0x = 0 to x=2x = 2.
  2. Set up integral: Set up the integral using the shell method. The radius of each cylindrical shell is xx, and the height is the function value y=x2y = x^2. The volume of each shell is approximately 2πxydx2\pi xy \, dx.
  3. Write integral for volume: Write the integral for the volume: V=022πx(x2)dxV = \int_{0}^{2} 2\pi x(x^2) \, dx. Simplify the integrand to 2πx32\pi x^3.
  4. Calculate integral: Calculate the integral: V=2π02x3dxV = 2\pi \int_{0}^{2} x^3 \, dx.
  5. Solve integral: Solve the integral: x3dx=x44\int x^3 \, dx = \frac{x^4}{4}. Evaluate from 00 to 22, which gives (244)(044)=1640=4\left(\frac{2^4}{4}\right) - \left(\frac{0^4}{4}\right) = \frac{16}{4} - 0 = 4.
  6. Multiply by 2π2\pi: Multiply by 2π2\pi: V=2π×4=8πV = 2\pi \times 4 = 8\pi cubic units.

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