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Use the Quadratic Formula to solve the quadratic below:\newlinex25x+9=0x^{2}-5x+9=0

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Q. Use the Quadratic Formula to solve the quadratic below:\newlinex25x+9=0x^{2}-5x+9=0
  1. Identify coefficients: Identify the coefficients aa, bb, and cc in the quadratic equation x25x+9=0x^2 - 5x + 9 = 0. By comparing x25x+9x^2 - 5x + 9 with the standard quadratic form ax2+bx+cax^2 + bx + c, we find that a=1a = 1, b=5b = -5, and c=9c = 9.
  2. Apply Quadratic Formula: Apply the Quadratic Formula to find the roots of the equation.\newlineThe Quadratic Formula is given by (b±b24ac)/(2a)(-b \pm \sqrt{b^2 - 4ac}) / (2a). We will substitute a=1a = 1, b=5b = -5, and c=9c = 9 into the formula.
  3. Substitute values: Substitute the values of aa, bb, and cc into the Quadratic Formula.\newline((5)±(5)2419)/(21)(-(-5) \pm \sqrt{(-5)^2 - 4\cdot1\cdot9}) / (2\cdot1) simplifies to (5±2536)/2(5 \pm \sqrt{25 - 36}) / 2.
  4. Simplify square root: Simplify the expression under the square root. 2536=1125 - 36 = -11, so the expression becomes (5±11)/2(5 \pm \sqrt{-11}) / 2.
  5. Complex roots: Since the value under the square root is negative, we will have complex roots. We can express 11\sqrt{-11} as 11×1\sqrt{11} \times \sqrt{-1}, where 1\sqrt{-1} is the imaginary unit ii. The expression becomes (5±11i)/2(5 \pm \sqrt{11}i) / 2.
  6. Divide by 22: Simplify the expression by dividing both terms by 22. \newline(52)±(112)i(\frac{5}{2}) \pm (\frac{\sqrt{11}}{2})i is the simplified form of the roots in a+bia+bi form.
  7. Write in a+bia+bi form: Write the roots in the simplest a+bia+bi form.\newlineThe roots are 52+(112)i\frac{5}{2} + \left(\frac{\sqrt{11}}{2}\right)i and 52(112)i\frac{5}{2} - \left(\frac{\sqrt{11}}{2}\right)i.

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