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Use the limit process to find the area of the region.\newliney=14x3,[2,4]y=\frac{1}{4}x^{3},[2,4]

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Q. Use the limit process to find the area of the region.\newliney=14x3,[2,4]y=\frac{1}{4}x^{3},[2,4]
  1. Set up integral: First, we need to set up the integral for the area under the curve from x=2x=2 to x=4x=4.\newlineWe use the formula for the definite integral of y=14x3y = \frac{1}{4}x^3 from x=2x = 2 to x=4x = 4.\newlineIntegral setup: 2414x3dx\int_{2}^{4} \frac{1}{4}x^3 \, dx
  2. Calculate antiderivative: Next, we calculate the antiderivative of (14)x3(\frac{1}{4})x^3. Antiderivative of (14)x3(\frac{1}{4})x^3 is (14)(14)x4=(116)x4(\frac{1}{4})\cdot(\frac{1}{4})x^4 = (\frac{1}{16})x^4. Now, we evaluate this from x=2x=2 to x=4x=4.
  3. Evaluate integral: Plug in the upper and lower limits of the integral.\newlineEvaluate at x=4x=4: (1/16)(44)=(1/16)(256)=16(1/16)(4^4) = (1/16)(256) = 16.\newlineEvaluate at x=2x=2: (1/16)(24)=(1/16)(16)=1(1/16)(2^4) = (1/16)(16) = 1.\newlineSubtract the lower limit evaluation from the upper limit evaluation: 161=1516 - 1 = 15.

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