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Use the following function rule to find f(6)f(6).\newlinef(x)=103+xf(x) = 10\sqrt{3 + x}\newlinef(6)=f(6) = _____

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Full solution

Q. Use the following function rule to find f(6)f(6).\newlinef(x)=103+xf(x) = 10\sqrt{3 + x}\newlinef(6)=f(6) = _____
  1. Identify Function and Input: Identify the function and the input value.\newlineWe are given the function f(x)=103+xf(x) = 10\sqrt{3 + x} and we need to find the value of f(6)f(6).
  2. Substitute Input into Function: Substitute the input value into the function.\newlineTo find f(6)f(6), we replace xx with 66 in the function f(x)f(x).\newlinef(6)=10(3+6)f(6) = 10\sqrt{(3 + 6)}
  3. Simplify Expression Inside Square Root: Simplify the expression inside the square root.\newlineCalculate the value inside the square root before multiplying by 1010.\newline3+6=93 + 6 = 9
  4. Take Square Root: Take the square root of the simplified expression.\newline9=3\sqrt{9} = 3
  5. Multiply by 1010: Multiply the result by 1010 to find f(6)f(6). \newlinef(6)=10×3f(6) = 10 \times 3\newlinef(6)=30f(6) = 30

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