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Use the following function rule to find f(49)f(49).\newlinef(x)=x−1f(x) = \sqrt{x} - 1\newlinef(49)=f(49) = _____

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Full solution

Q. Use the following function rule to find f(49)f(49).\newlinef(x)=x−1f(x) = \sqrt{x} - 1\newlinef(49)=f(49) = _____
  1. Identify function rule and input: Identify the function rule and the input value.\newlineThe function rule given is f(x)=x−1f(x) = \sqrt{x} - 1, and we need to find the value of f(49)f(49).
  2. Substitute input into rule: Substitute the input value into the function rule.\newlineTo find f(49)f(49), we substitute 4949 for xx in the function rule:\newlinef(49)=49−1f(49) = \sqrt{49} - 1
  3. Calculate square root: Calculate the square root of the input value.\newlineThe square root of 4949 is 77, so we have:\newlinef(49)=7−1f(49) = 7 - 1
  4. Subtract to find final value: Subtract 11 from the square root to find the final value.\newlinef(49)=7−1f(49) = 7 - 1\newlinef(49)=6f(49) = 6

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