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Use the following function rule to find f(49)f(49).\newlinef(x)=7+12xf(x) = 7 + 12\sqrt{x}\newlinef(49)=f(49) = _____

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Q. Use the following function rule to find f(49)f(49).\newlinef(x)=7+12xf(x) = 7 + 12\sqrt{x}\newlinef(49)=f(49) = _____
  1. Identify Function and Input: Identify the function and the input value.\newlineWe are given the function f(x)=7+12xf(x) = 7 + 12\sqrt{x} and we need to find the value of f(49)f(49).
  2. Substitute Input into Function: Substitute the input value into the function.\newlinef(49)=7+1249f(49) = 7 + 12\sqrt{49}
  3. Calculate Square Root: Calculate the square root of 4949.49=7\sqrt{49} = 7
  4. Substitute Square Root Value: Substitute the square root value into the function.\newlinef(49)=7+12×7f(49) = 7 + 12 \times 7
  5. Multiply and Add: Multiply 1212 by 77. \newline12×7=8412 \times 7 = 84
  6. Calculate Final Result: Add 77 to the product of 1212 and 77. \newlinef(49)=7+84f(49) = 7 + 84
  7. Calculate Final Result: Add 77 to the product of 1212 and 77.
    f(49)=7+84f(49) = 7 + 84 Calculate the final result.
    f(49)=91f(49) = 91

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