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Use the following function rule to find f(40)f(40).\newlinef(x)=109+xf(x) = 10\sqrt{9 + x}\newlinef(40)=f(40) = _____

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Q. Use the following function rule to find f(40)f(40).\newlinef(x)=109+xf(x) = 10\sqrt{9 + x}\newlinef(40)=f(40) = _____
  1. Identify Function & Input: Identify the function and the input value.\newlineWe are given the function f(x)=109+xf(x) = 10\sqrt{9 + x} and we need to find the value of f(40)f(40).
  2. Substitute Input: Substitute the input value into the function.\newlineTo find f(40)f(40), we substitute xx with 4040 in the function:\newlinef(40)=109+40f(40) = 10\sqrt{9 + 40}
  3. Addition Calculation: Perform the addition inside the square root.\newlineCalculate the value inside the square root:\newline9+40=499 + 40 = 49
  4. Square Root Calculation: Calculate the square root.\newlineFind the square root of 4949:\newline49=7\sqrt{49} = 7
  5. Multiply by Coefficient: Multiply the square root by the coefficient.\newlineMultiply the result from Step 44 by the coefficient 1010:\newlinef(40)=10×7f(40) = 10 \times 7
  6. Final Calculation: Perform the multiplication to find the final answer.\newlineCalculate the final result:\newlinef(40)=70f(40) = 70

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