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Use the following function rule to find f(36)f(36).\newlinef(x)=6x+2f(x) = 6\sqrt{x} + 2\newlinef(36)=f(36) = _____

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Q. Use the following function rule to find f(36)f(36).\newlinef(x)=6x+2f(x) = 6\sqrt{x} + 2\newlinef(36)=f(36) = _____
  1. Identify Function and Input: Identify the function and the input value.\newlineWe are given the function f(x)=6x+2f(x) = 6\sqrt{x} + 2 and we need to find the value of f(36)f(36).
  2. Substitute Input into Function: Substitute the input value into the function.\newlineTo find f(36)f(36), we substitute xx with 3636 in the function f(x)f(x).\newlinef(36)=636+2f(36) = 6\sqrt{36} + 2
  3. Calculate Square Root: Calculate the square root of the input value.\newlineThe square root of 3636 is 66, since 6×6=366 \times 6 = 36.\newlinef(36)=6×6+2f(36) = 6 \times 6 + 2
  4. Multiply and Add: Multiply and add to find the final value.\newlineNow we perform the multiplication and addition.\newlinef(36)=6×6+2f(36) = 6 \times 6 + 2\newlinef(36)=36+2f(36) = 36 + 2\newlinef(36)=38f(36) = 38

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