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Use the following function rule to find f(36)f(36).\newlinef(x)=4+2xf(x) = 4 + 2\sqrt{x}\newlinef(36)=f(36) = _____

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Q. Use the following function rule to find f(36)f(36).\newlinef(x)=4+2xf(x) = 4 + 2\sqrt{x}\newlinef(36)=f(36) = _____
  1. Identify Function and Input: Identify the function and the input value.\newlineWe are given the function f(x)=4+2xf(x) = 4 + 2\sqrt{x} and we need to find the value of f(36)f(36).
  2. Substitute Input into Function: Substitute the input value into the function. f(36)=4+236f(36) = 4 + 2\sqrt{36}
  3. Calculate Square Root: Calculate the square root of the input value. 36=6\sqrt{36} = 6
  4. Continue Calculation with Square Root: Continue the calculation with the square root result. f(36)=4+2×6f(36) = 4 + 2 \times 6
  5. Multiply and Add: Multiply 22 by the square root result.\newline2×6=122 \times 6 = 12
  6. Complete Addition: Add the multiplication result to the constant term in the function.\newlinef(36)=4+12f(36) = 4 + 12
  7. Complete Addition: Add the multiplication result to the constant term in the function.\newlinef(36)=4+12f(36) = 4 + 12Complete the addition to find the final value of f(36)f(36).\newlinef(36)=16f(36) = 16

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