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Let’s check out your problem:
Use the FOIL method to find the product.
\newline
(
5
z
−
u
)
(
2
z
+
4
u
)
(5 z-u)(2 z+4 u)
(
5
z
−
u
)
(
2
z
+
4
u
)
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Math Problems
Algebra 1
Multiply two binomials
Full solution
Q.
Use the FOIL method to find the product.
\newline
(
5
z
−
u
)
(
2
z
+
4
u
)
(5 z-u)(2 z+4 u)
(
5
z
−
u
)
(
2
z
+
4
u
)
Multiply First terms:
First, multiply the First terms:
5
z
×
2
z
=
10
z
2
5z \times 2z = 10z^2
5
z
×
2
z
=
10
z
2
.
Multiply Outer terms:
Next, multiply the Outer terms:
5
z
×
4
u
=
20
z
u
5z \times 4u = 20zu
5
z
×
4
u
=
20
z
u
.
Multiply Inner terms:
Then, multiply the Inner terms:
−
u
×
2
z
=
−
2
u
z
-u \times 2z = -2uz
−
u
×
2
z
=
−
2
u
z
(which is the same as
−
2
z
u
-2zu
−
2
z
u
).
Multiply Last terms:
Finally, multiply the Last terms:
−
u
×
4
u
=
−
4
u
2
-u \times 4u = -4u^2
−
u
×
4
u
=
−
4
u
2
.
Add all products:
Now, add all the products together:
10
z
2
+
20
z
u
−
2
z
u
−
4
u
2
10z^2 + 20zu - 2zu - 4u^2
10
z
2
+
20
z
u
−
2
z
u
−
4
u
2
.
Combine like terms:
Combine like terms:
20
z
u
−
2
z
u
=
18
z
u
20zu - 2zu = 18zu
20
z
u
−
2
z
u
=
18
z
u
. So, the simplified form is
10
z
2
+
18
z
u
−
4
u
2
10z^2 + 18zu - 4u^2
10
z
2
+
18
z
u
−
4
u
2
.
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\newline
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−
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\newline
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\text{[[even][odd][neither]]}
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+
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)
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r
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)
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\newline
(
x
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(
x
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)
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(
x
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)
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x
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\newline
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\newline
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