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Use the exponent laws to simplify each expression. Leave your answers with positive exponents.
a) 
(x^(3))(x^((-2)/(3)))
b) 
(81^(-0.25))^(3)
c) 
((m^(-2))^((2)/(3)))/((m^((1)/(2)))^(4))
d) 
(9p^(2))^(-(1)/(2))(p^(-(3)/(2)))
e) 
[(x^(-2))/((xy)^(4))]^(1.5)
f) 
[(4x^(-2))/(9y^(-4))]^(-(5)/(2))
For each of the following, use the exponent laws to help identify a value for 
p that satisfies the equation.
a) 
(x^(p))^((1)/(3))=x^((2)/(3))
b) 
(x^(p))(x^((3)/(4)))=x^(2)
c) 
(x^(p))/(x^(-2))=x^((5)/(2))
d) 
(-3x^((5)/(2)))(px^(-(1)/(2)))=(-3)/(4)x^(2)
e) 
((9a^(-4))/(25))^(p)=(3)/(5a^(2))
f) 
(2^(-p))(3^(p))=(27)/(8)
Evaluate without using a calculator. Leave your answers as rational numbers.
a) 
8^((2)/(3))
b) 
16^((1)/(4))
c) 
-27^((4)/(3))
d) 
(3^((1)/(6)))(3^((5)/(6)))
e) 
((36x^(0))/(25))^(1.5)
f) 
(6^(-2))/(36^(-(1)/(2)))
Evaluate using a calculator. Express your answers to four decimal places, if necessary.
a) 
(81^(-0.25))^(3)
b) 
(8^(3))(8^(1.2))
d) 
((2^(3))/(8^(2)))^((2)/(3))
e) 
((-64)/(6^((1)/(2))))^((4)/(3))
c) 
((2^(5))/(5^(2)))^(-(3)/(2))
f) 
((2^((1)/(2)))^(3))/(16)

22. Use the exponent laws to simplify each expression. Leave your answers with positive exponents.\newlinea) (x3)(x23) \left(x^{3}\right)\left(x^{\frac{-2}{3}}\right) \newlineb) (810.25)3 \left(81^{-0.25}\right)^{3} \newlinec) (m2)23(m12)4 \frac{\left(m^{-2}\right)^{\frac{2}{3}}}{\left(m^{\frac{1}{2}}\right)^{4}} \newlined) (9p2)12(p32) \left(9 p^{2}\right)^{-\frac{1}{2}}\left(p^{-\frac{3}{2}}\right) \newlinee) [x2(xy)4]1.5 \left[\frac{x^{-2}}{(x y)^{4}}\right]^{1.5} \newlinef) [4x29y4]52 \left[\frac{4 x^{-2}}{9 y^{-4}}\right]^{-\frac{5}{2}} \newline33. For each of the following, use the exponent laws to help identify a value for p p that satisfies the equation.\newlinea) (xp)13=x23 \left(x^{p}\right)^{\frac{1}{3}}=x^{\frac{2}{3}} \newlineb) (xp)(x34)=x2 \left(x^{p}\right)\left(x^{\frac{3}{4}}\right)=x^{2} \newlinec) xpx2=x52 \frac{x^{p}}{x^{-2}}=x^{\frac{5}{2}} \newlined) (810.25)3 \left(81^{-0.25}\right)^{3} 00\newlinee) (810.25)3 \left(81^{-0.25}\right)^{3} 11\newlinef) (810.25)3 \left(81^{-0.25}\right)^{3} 22\newline44. Evaluate without using a calculator. Leave your answers as rational numbers.\newlinea) (810.25)3 \left(81^{-0.25}\right)^{3} 33\newlineb) (810.25)3 \left(81^{-0.25}\right)^{3} 44\newlinec) (810.25)3 \left(81^{-0.25}\right)^{3} 55\newlined) (810.25)3 \left(81^{-0.25}\right)^{3} 66\newlinee) (810.25)3 \left(81^{-0.25}\right)^{3} 77\newlinef) (810.25)3 \left(81^{-0.25}\right)^{3} 88\newline55. Evaluate using a calculator. Express your answers to four decimal places, if necessary.\newlinea) (810.25)3 \left(81^{-0.25}\right)^{3} \newlineb) (m2)23(m12)4 \frac{\left(m^{-2}\right)^{\frac{2}{3}}}{\left(m^{\frac{1}{2}}\right)^{4}} 00\newlined) (m2)23(m12)4 \frac{\left(m^{-2}\right)^{\frac{2}{3}}}{\left(m^{\frac{1}{2}}\right)^{4}} 11\newlinee) (m2)23(m12)4 \frac{\left(m^{-2}\right)^{\frac{2}{3}}}{\left(m^{\frac{1}{2}}\right)^{4}} 22\newlinec) (m2)23(m12)4 \frac{\left(m^{-2}\right)^{\frac{2}{3}}}{\left(m^{\frac{1}{2}}\right)^{4}} 33\newlinef) (m2)23(m12)4 \frac{\left(m^{-2}\right)^{\frac{2}{3}}}{\left(m^{\frac{1}{2}}\right)^{4}} 44

Full solution

Q. 22. Use the exponent laws to simplify each expression. Leave your answers with positive exponents.\newlinea) (x3)(x23) \left(x^{3}\right)\left(x^{\frac{-2}{3}}\right) \newlineb) (810.25)3 \left(81^{-0.25}\right)^{3} \newlinec) (m2)23(m12)4 \frac{\left(m^{-2}\right)^{\frac{2}{3}}}{\left(m^{\frac{1}{2}}\right)^{4}} \newlined) (9p2)12(p32) \left(9 p^{2}\right)^{-\frac{1}{2}}\left(p^{-\frac{3}{2}}\right) \newlinee) [x2(xy)4]1.5 \left[\frac{x^{-2}}{(x y)^{4}}\right]^{1.5} \newlinef) [4x29y4]52 \left[\frac{4 x^{-2}}{9 y^{-4}}\right]^{-\frac{5}{2}} \newline33. For each of the following, use the exponent laws to help identify a value for p p that satisfies the equation.\newlinea) (xp)13=x23 \left(x^{p}\right)^{\frac{1}{3}}=x^{\frac{2}{3}} \newlineb) (xp)(x34)=x2 \left(x^{p}\right)\left(x^{\frac{3}{4}}\right)=x^{2} \newlinec) xpx2=x52 \frac{x^{p}}{x^{-2}}=x^{\frac{5}{2}} \newlined) (810.25)3 \left(81^{-0.25}\right)^{3} 00\newlinee) (810.25)3 \left(81^{-0.25}\right)^{3} 11\newlinef) (810.25)3 \left(81^{-0.25}\right)^{3} 22\newline44. Evaluate without using a calculator. Leave your answers as rational numbers.\newlinea) (810.25)3 \left(81^{-0.25}\right)^{3} 33\newlineb) (810.25)3 \left(81^{-0.25}\right)^{3} 44\newlinec) (810.25)3 \left(81^{-0.25}\right)^{3} 55\newlined) (810.25)3 \left(81^{-0.25}\right)^{3} 66\newlinee) (810.25)3 \left(81^{-0.25}\right)^{3} 77\newlinef) (810.25)3 \left(81^{-0.25}\right)^{3} 88\newline55. Evaluate using a calculator. Express your answers to four decimal places, if necessary.\newlinea) (810.25)3 \left(81^{-0.25}\right)^{3} \newlineb) (m2)23(m12)4 \frac{\left(m^{-2}\right)^{\frac{2}{3}}}{\left(m^{\frac{1}{2}}\right)^{4}} 00\newlined) (m2)23(m12)4 \frac{\left(m^{-2}\right)^{\frac{2}{3}}}{\left(m^{\frac{1}{2}}\right)^{4}} 11\newlinee) (m2)23(m12)4 \frac{\left(m^{-2}\right)^{\frac{2}{3}}}{\left(m^{\frac{1}{2}}\right)^{4}} 22\newlinec) (m2)23(m12)4 \frac{\left(m^{-2}\right)^{\frac{2}{3}}}{\left(m^{\frac{1}{2}}\right)^{4}} 33\newlinef) (m2)23(m12)4 \frac{\left(m^{-2}\right)^{\frac{2}{3}}}{\left(m^{\frac{1}{2}}\right)^{4}} 44
  1. Use Product of Powers Property: a) (x3)(x(2)/(3))(x^{3})(x^{(-2)/(3)})\newlineUse the product of powers property: anam=a(n+m)a^n \ast a^m = a^{(n+m)}\newlinex(3+(2/3))=x(9/32/3)=x(7/3)x^{(3 + (-2/3))} = x^{(9/3 - 2/3)} = x^{(7/3)}
  2. Use Power of a Power Property: b) (810.25)3(81^{-0.25})^3\newlineUse the power of a power property: (an)m=anm(a^n)^m = a^{n*m}\newline810.253=810.7581^{-0.25 * 3} = 81^{-0.75}
  3. Use Power of a Power Property: c) ((m2)(2)/(3))/((m(1)/(2))4)((m^{-2})^{(2)/(3)})/((m^{(1)/(2)})^{4})\newlineUse the power of a power property: (an)m=anm(a^n)^m = a^{n*m}\newlinem(2)(2/3)/m(1/2)4=m4/3/m2m^{(-2)*(2/3)} / m^{(1/2)*4} = m^{-4/3} / m^2\newlineUse the quotient of powers property: an/am=anma^n / a^m = a^{n-m}\newlinem4/32=m4/36/3=m10/3m^{-4/3 - 2} = m^{-4/3 - 6/3} = m^{-10/3}
  4. Use Power of a Product Property: d) (9p2)(1)/(2))(p(3)/(2))(9p^{2})^{-(1)/(2)})(p^{-(3)/(2)})\newlineUse the power of a product property: (ab)n=anbn(a*b)^{n} = a^{n} * b^{n}\newline(9(1)/(2))(p2(1)/(2))(p(3)/(2))(9^{-(1)/(2)})(p^{2*(-1)/(2)})(p^{-(3)/(2)})\newlineSimplify each term:\newline9(1/2)p(1)p(3/2)9^{(-1/2)} * p^{(-1)} * p^{(-3/2)}\newlineCombine the p terms using the product of powers property:\newline9(1/2)p(13/2)=9(1/2)p(5/2)9^{(-1/2)} * p^{(-1 - 3/2)} = 9^{(-1/2)} * p^{(-5/2)}
  5. Use Power of a Quotient Property: e) [(x2)/((xy)4)]1.5[(x^{-2})/((xy)^{4})]^{1.5} Use the power of a quotient property: (a/b)n=an/bn(a/b)^n = a^n / b^n (x21.5)/((xy)41.5)(x^{-2\cdot1.5})/((xy)^{4\cdot1.5}) Simplify each term: x3/(x6y6)x^{-3} / (x^{6}y^{6}) Use the quotient of powers property: x36/y6=x9/y6x^{-3 - 6} / y^{6} = x^{-9} / y^{6}
  6. Use Power of a Quotient Property: f) [(4x2)/(9y4)]52[(4x^{-2})/(9y^{-4})]^{-\frac{5}{2}}\newlineUse the power of a quotient property: (a/b)n=an/bn(a/b)^n = a^n / b^n\newline(452)(x2(52))/(952)(y4(52))(4^{-\frac{5}{2}})(x^{-2*(-\frac{5}{2})})/(9^{-\frac{5}{2}})(y^{-4*(-\frac{5}{2})})\newlineSimplify each term:\newline452x5/952y204^{-\frac{5}{2}} * x^{5} / 9^{-\frac{5}{2}} * y^{20}\newlineCombine the terms using the product of powers property:\newline(452/952)(x5y20)(4^{-\frac{5}{2}} / 9^{-\frac{5}{2}}) * (x^{5} * y^{20})
  7. Use Power of a Quotient Property: a) (xp)(1)/(3)=x(2)/(3)(x^{p})^{(1)/(3)}=x^{(2)/(3)}\newlineUse the power of a power property: (an)m=anm(a^n)^m = a^{n*m}\newlinexp(1/3)=x2/3x^{p*(1/3)} = x^{2/3}\newlineSet the exponents equal to each other to find pp:\newlinep(1/3)=2/3p*(1/3) = 2/3\newlineMultiply both sides by 33 to solve for pp:\newlinep=2p = 2
  8. Use Power of a Product Property: b) (xp)(x34)=x2(x^{p})(x^{\frac{3}{4}})=x^{2} Use the product of powers property: anam=an+ma^n \cdot a^m = a^{n+m} xp+34=x2x^{p + \frac{3}{4}} = x^{2} Set the exponents equal to each other to find pp: p+34=2p + \frac{3}{4} = 2 Subtract 34\frac{3}{4} from both sides to solve for pp: p=234=114p = 2 - \frac{3}{4} = 1 \frac{1}{4} or 54\frac{5}{4}
  9. Use Power of a Quotient Property: c) (xp)/(x2)=x(5)/(2)(x^{p})/(x^{-2})=x^{(5)/(2)}\newlineUse the quotient of powers property: an/am=a(nm)a^n / a^m = a^{(n-m)}\newlinex(p(2))=x(5/2)x^{(p - (-2))} = x^{(5/2)}\newlineSet the exponents equal to each other to find pp:\newlinep+2=5/2p + 2 = 5/2\newlineSubtract 22 from both sides to solve for pp:\newlinep=5/24/2=1/2p = 5/2 - 4/2 = 1/2
  10. Use Property of Equality: d) (3x(5)/(2))(px(1)/(2))=(3)/(4)x2(-3x^{(5)/(2)})(px^{-(1)/(2)})=(-3)/(4)x^{2}\newlineDistribute the x terms:\newline3px5/21/2=3/4x2-3p \cdot x^{5/2 - 1/2} = -3/4 \cdot x^{2}\newlineSimplify the x terms:\newline3px4/2=3/4x2-3p \cdot x^{4/2} = -3/4 \cdot x^{2}\newline3px2=3/4x2-3p \cdot x^{2} = -3/4 \cdot x^{2}\newlineSet the coefficients equal to each other to find p:\newline3p=3/4-3p = -3/4\newlineDivide both sides by 3-3 to solve for p:\newlinep=1/4p = 1/4
  11. Use Property of Equality: d) (3x(5)/(2))(px(1)/(2))=(3)/(4)x2(-3x^{(5)/(2)})(px^{-(1)/(2)})=(-3)/(4)x^{2}\newlineDistribute the x terms:\newline3px5/21/2=3/4x2-3p \cdot x^{5/2 - 1/2} = -3/4 \cdot x^{2}\newlineSimplify the x terms:\newline3px4/2=3/4x2-3p \cdot x^{4/2} = -3/4 \cdot x^{2}\newline3px2=3/4x2-3p \cdot x^{2} = -3/4 \cdot x^{2}\newlineSet the coefficients equal to each other to find pp:\newline3p=3/4-3p = -3/4\newlineDivide both sides by 3-3 to solve for pp:\newlinep=1/4p = 1/4e) ((9a4)/(25))p=(3)/(5a2)((9a^{-4})/(25))^{p}=(3)/(5a^{2})\newlineUse the power of a quotient property: 3px5/21/2=3/4x2-3p \cdot x^{5/2 - 1/2} = -3/4 \cdot x^{2}00\newline3px5/21/2=3/4x2-3p \cdot x^{5/2 - 1/2} = -3/4 \cdot x^{2}11\newlineSet the 3px5/21/2=3/4x2-3p \cdot x^{5/2 - 1/2} = -3/4 \cdot x^{2}22 terms equal to each other to find pp:\newline3px5/21/2=3/4x2-3p \cdot x^{5/2 - 1/2} = -3/4 \cdot x^{2}44\newlineSet the exponents equal to each other to find pp:\newline3px5/21/2=3/4x2-3p \cdot x^{5/2 - 1/2} = -3/4 \cdot x^{2}66\newlineDivide both sides by 3px5/21/2=3/4x2-3p \cdot x^{5/2 - 1/2} = -3/4 \cdot x^{2}77 to solve for pp:\newline3px5/21/2=3/4x2-3p \cdot x^{5/2 - 1/2} = -3/4 \cdot x^{2}99
  12. Use Property of Equality: d) (3x(5)/(2))(px(1)/(2))=(3)/(4)x2(-3x^{(5)/(2)})(px^{-(1)/(2)})=(-3)/(4)x^{2}\newlineDistribute the x terms:\newline3px5/21/2=3/4x2-3p \cdot x^{5/2 - 1/2} = -3/4 \cdot x^{2}\newlineSimplify the x terms:\newline3px4/2=3/4x2-3p \cdot x^{4/2} = -3/4 \cdot x^{2}\newline3px2=3/4x2-3p \cdot x^{2} = -3/4 \cdot x^{2}\newlineSet the coefficients equal to each other to find pp:\newline3p=3/4-3p = -3/4\newlineDivide both sides by 3-3 to solve for pp:\newlinep=1/4p = 1/4e) ((9a4)/(25))p=(3)/(5a2)((9a^{-4})/(25))^{p}=(3)/(5a^{2})\newlineUse the power of a quotient property: 3px5/21/2=3/4x2-3p \cdot x^{5/2 - 1/2} = -3/4 \cdot x^{2}00\newline3px5/21/2=3/4x2-3p \cdot x^{5/2 - 1/2} = -3/4 \cdot x^{2}11\newlineSet the 3px5/21/2=3/4x2-3p \cdot x^{5/2 - 1/2} = -3/4 \cdot x^{2}22 terms equal to each other to find pp:\newline3px5/21/2=3/4x2-3p \cdot x^{5/2 - 1/2} = -3/4 \cdot x^{2}44\newlineSet the exponents equal to each other to find pp:\newline3px5/21/2=3/4x2-3p \cdot x^{5/2 - 1/2} = -3/4 \cdot x^{2}66\newlineDivide both sides by 3px5/21/2=3/4x2-3p \cdot x^{5/2 - 1/2} = -3/4 \cdot x^{2}77 to solve for pp:\newline3px5/21/2=3/4x2-3p \cdot x^{5/2 - 1/2} = -3/4 \cdot x^{2}99f) 3px4/2=3/4x2-3p \cdot x^{4/2} = -3/4 \cdot x^{2}00\newlineUse the property of equality for exponents:\newline3px4/2=3/4x2-3p \cdot x^{4/2} = -3/4 \cdot x^{2}11\newlineSet the bases equal to each other to find pp:\newline3px4/2=3/4x2-3p \cdot x^{4/2} = -3/4 \cdot x^{2}33\newlineSince the bases are different, we cannot directly compare the exponents. This step is incorrect.

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