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Use point-slope form to write the equation of a line that passes through the point (18,-3) with slope -2 . Answer:

Use point-slope form to write the equation of a line that passes through the point (18,−3) (18,-3) with slope −2-2 .\newlineAnswer:

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Q. Use point-slope form to write the equation of a line that passes through the point (18,−3) (18,-3) with slope −2-2 .\newlineAnswer:
  1. Recall Point-Slope Form: Recall the point-slope form of a line's equation. The point-slope form of a line's equation is given by: y−y1=m(x−x1)y - y_1 = m(x - x_1), where mm is the slope and (x1,y1)(x_1, y_1) is a point on the line.
  2. Identify Slope and Point: Identify the slope (mm) and the point (x1,y1x_1, y_1) through which the line passes.\newlineSlope (mm): −2-2\newlinePoint (x1,y1x_1, y_1): (18,−3)(18, -3)
  3. Substitute into Equation: Substitute the slope and point into the point-slope form equation.\newlineUsing the point-slope form, y−y1=m(x−x1)y - y_1 = m(x - x_1), we substitute m=−2m = -2, x1=18x_1 = 18, and y1=−3y_1 = -3.\newliney−(−3)=−2(x−18)y - (-3) = -2(x - 18)
  4. Simplify the Equation: Simplify the equation.\newliney+3=−2(x−18)y + 3 = -2(x - 18)\newliney+3=−2x+36y + 3 = -2x + 36
  5. Write Final Equation: Write the final equation in point-slope form.\newlineThe final equation of the line in point-slope form is:\newliney+3=−2x+36y + 3 = -2x + 36

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