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Use Pascal's Triangle to expand 
(3y^(2)-2)^(3). Express your answer in simplest form.
Answer:

Use Pascal's Triangle to expand (3y22)3 \left(3 y^{2}-2\right)^{3} . Express your answer in simplest form.\newlineAnswer:

Full solution

Q. Use Pascal's Triangle to expand (3y22)3 \left(3 y^{2}-2\right)^{3} . Express your answer in simplest form.\newlineAnswer:
  1. Identify Exponent Row: Identify the row of Pascal's Triangle that corresponds to the exponent 33. The third row of Pascal's Triangle (starting with row 00) is 1,3,3,11, 3, 3, 1. These numbers will be the coefficients in the expansion.
  2. Write Expansion Terms: Write out the terms of the expansion using the binomial theorem and the coefficients from Pascal's Triangle.\newlineThe expansion will have four terms, with the coefficients 11, 33, 33, and 11, respectively. The first term will have (3y2)3(3y^2)^3, the second term will have (3y2)2(3y^2)^2 multiplied by 2-2, the third term will have (3y2)(3y^2) multiplied by (2)2(-2)^2, and the fourth term will have (2)3(-2)^3.
  3. Calculate Each Term: Calculate each term of the expansion.\newlineFirst term: (3y2)3=27y6(3y^2)^3 = 27y^6\newlineSecond term: 3×(3y2)2×(2)=3×9y4×(2)=54y43 \times (3y^2)^2 \times (-2) = 3 \times 9y^4 \times (-2) = -54y^4\newlineThird term: 3×(3y2)×(2)2=3×3y2×4=36y23 \times (3y^2) \times (-2)^2 = 3 \times 3y^2 \times 4 = 36y^2\newlineFourth term: (2)3=8(-2)^3 = -8
  4. Combine Terms: Combine all the terms to write the expanded form.\newlineThe expanded form is 27y654y4+36y2827y^6 - 54y^4 + 36y^2 - 8.

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