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Two-variable equations: Quiz 3
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y=-(3)/(2)x-3.
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Two-variable equations: Quiz 33\newlineGraph y=32x3 y=-\frac{3}{2} x-3 .\newlineCheck

Full solution

Q. Two-variable equations: Quiz 33\newlineGraph y=32x3 y=-\frac{3}{2} x-3 .\newlineCheck
  1. Plot y-intercept: Plot the y-intercept on the graph.\newlineThe y-intercept is where x=0x=0, so plug x=0x=0 into the equation to find yy.\newliney=(32)(0)3y = -\left(\frac{3}{2}\right)(0) - 3\newliney=3y = -3\newlineSo the y-intercept is (0,3)(0, -3).
  2. Find slope: Find the slope of the line.\newlineThe slope is the coefficient of xx, which is (32)-\left(\frac{3}{2}\right).\newlineThis means for every 22 units we move to the right (positive xx direction), we move 33 units down (negative yy direction) because the slope is negative.
  3. Plot another point: Plot another point using the slope.\newlineStarting from the y-intercept (0,3)(0, -3), move 22 units to the right and 33 units down.\newlineThis gives us the point (2,6)(2, -6).\newlinePlot the point (2,6)(2, -6) on the graph.
  4. Draw the line: Draw the line through the points (0,3)(0, -3) and (2,6)(2, -6). Use a ruler to make sure the line is straight.
  5. Check line: Check if the line is correct.\newlineChoose a point not already used, like (4,9)(4, -9).\newlinePlug x=4x=4 into the equation to see if yy equals 9-9.\newliney=(32)(4)3y = -\left(\frac{3}{2}\right)(4) - 3\newliney=63y = -6 - 3\newliney=9y = -9\newlineThe point (4,9)(4, -9) lies on the line, so the graph is correct.

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