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Two containers designed to hold water are side by side, both in the shape of a cylinder. Container A has a diameter of 1616 feet and a height of 88 feet. Container B has a diameter of 88 feet and a height of 1818 feet. Container A is full of water and the water is pumped into Container B until Container B is completely full. After the pumping is complete, what is the volume of the empty space inside Container A, to the nearest tenth of a cubic foot?

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Q. Two containers designed to hold water are side by side, both in the shape of a cylinder. Container A has a diameter of 1616 feet and a height of 88 feet. Container B has a diameter of 88 feet and a height of 1818 feet. Container A is full of water and the water is pumped into Container B until Container B is completely full. After the pumping is complete, what is the volume of the empty space inside Container A, to the nearest tenth of a cubic foot?
  1. Calculate Volume Container A: Calculate the volume of Container A using the formula for the volume of a cylinder, V=πr2hV = \pi r^2 h, where rr is the radius and hh is the height. The radius of Container A is half the diameter, so r=16 feet2=8 feetr = \frac{16 \text{ feet}}{2} = 8 \text{ feet}. The height h=8 feeth = 8 \text{ feet}. V=π(8 feet)2(8 feet)V = \pi(8 \text{ feet})^2(8 \text{ feet}).
  2. Calculate Volume Container B: Perform the calculation for the volume of Container A: V=π(64)(8)=π(512)V = \pi(64)(8) = \pi(512) cubic feet.
  3. Subtract Volumes: Calculate the volume of Container B using the same formula, V=πr2hV = \pi r^2 h. The radius of Container B is half the diameter, so r=8 feet2=4 feetr = \frac{8 \text{ feet}}{2} = 4 \text{ feet}. The height h=18 feeth = 18 \text{ feet}. V=π(4 feet)2(18 feet)V = \pi(4 \text{ feet})^2(18 \text{ feet}).
  4. Perform Subtraction: Perform the calculation for the volume of Container B: V=π(16)(18)=π(288)V = \pi(16)(18) = \pi(288) cubic feet.
  5. Calculate Empty Space Volume: Subtract the volume of Container B from the volume of Container A to find the empty space in Container A. Volume of Container A - Volume of Container B = π(512)\pi(512) cubic feet - π(288)\pi(288) cubic feet.
  6. Use Approximation: Perform the subtraction: π(512)π(288)=π(224)\pi(512) - \pi(288) = \pi(224) cubic feet. This is the volume of the empty space in Container A.
  7. Use Approximation: Perform the subtraction: π(512)π(288)=π(224)\pi(512) - \pi(288) = \pi(224) cubic feet. This is the volume of the empty space in Container A.Use the value of π\pi as approximately 3.143.14 to calculate the volume of the empty space in Container A to the nearest tenth: 3.14×224703.363.14 \times 224 \approx 703.36 cubic feet.

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