Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Tritium is a radioactive isotope of hydrogen that decays by about 5%5\% per year. A large bottle of water that contained 450,000450,000 tritium atoms remained undisturbed for 1111 years. How much tritium does the bottle contain now? If necessary, round your answer to the nearest whole number.\newline____ tritium atoms\newline

Full solution

Q. Tritium is a radioactive isotope of hydrogen that decays by about 5%5\% per year. A large bottle of water that contained 450,000450,000 tritium atoms remained undisturbed for 1111 years. How much tritium does the bottle contain now? If necessary, round your answer to the nearest whole number.\newline____ tritium atoms\newline
  1. Determine Decay Type: Determine the type of decay process. Tritium decays by 5%5\% per year, which indicates an exponential decay process.
  2. Identify Initial Amount: Identify the initial amount aa and the decay rate rr. The initial amount of tritium atoms is a=450,000a = 450,000. The decay rate per year is r=5%r = 5\% or 0.050.05 when expressed as a decimal.
  3. Calculate Remaining Amount: Calculate the remaining amount of tritium after 1111 years using the exponential decay formula.\newlineThe formula for exponential decay is P(t)=a(1r)tP(t) = a(1 - r)^t, where P(t)P(t) is the amount of substance remaining after time tt, aa is the initial amount, rr is the decay rate, and tt is the time in years.
  4. Substitute Values: Substitute the known values into the exponential decay formula. P(11)=450,000(10.05)11P(11) = 450,000(1 - 0.05)^{11}
  5. Calculate Remaining Amount: Calculate the remaining amount of tritium. \newlineP(11)=450,000(0.95)11P(11) = 450,000(0.95)^{11}\newlineP(11)450,000(0.571753)11P(11) \approx 450,000(0.571753)^{11}\newlineP(11)450,000×0.571753P(11) \approx 450,000 \times 0.571753\newlineP(11)257,288.85P(11) \approx 257,288.85
  6. Round Answer: Round the answer to the nearest whole number.\newlineThe remaining amount of tritium is approximately 257,289257,289 atoms.

More problems from Exponential growth and decay: word problems