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Tom was asked to determine whether 
f(x)=x^(3)+x is even, odd, or neither. Here is his work:
Step 1: Find expression for 
f(-x)

{:[f(-x)=(-x)^(3)+x],[=-x^(3)+x]:}
Step 2: Check if 
f(-x) is equal to 
f(x) or 
-f(x)

-x^(3)+x isn't the same as 
f(x)=x^(3)+x or 
-f(x)=-x^(3)-x.
Step 3: Conclusion

f(-x) isn't equivalent to either 
f(x) or 
-f(x), so 
f is neither even nor odd.
Is Tom's work correct? If not, what is the first step where Tom made a mistake?
Choose 1 answer:
(A) Tom's work is correct.
(B) Tom's work is incorrect. He first made a mistake in Step 1.
(C) Tom's work is incorrect. He first made a mistake in Step 2.
(D) Tom's work is incorrect. He first made a mistake in Step 3.

Tom was asked to determine whether f(x)=x3+x f(x)=x^{3}+x is even, odd, or neither. Here is his work:\newlineStep 11: Find expression for f(x) f(-x) \newlinef(x)=(x)3+x=x3+x \begin{aligned} f(-x) & =(-x)^{3}+x \\ & =-x^{3}+x \end{aligned} \newlineStep 22: Check if f(x) f(-x) is equal to f(x) f(x) or f(x) -f(x) \newlinex3+x -x^{3}+x isn't the same as f(x)=x3+x f(x)=x^{3}+x or f(x)=x3x -f(x)=-x^{3}-x .\newlineStep 33: Conclusion\newlinef(x) f(-x) isn't equivalent to either f(x) f(x) or f(x) -f(x) , so f f is neither even nor odd.\newlineIs Tom's work correct? If not, what is the first step where Tom made a mistake?\newlineChoose 11 answer:\newline(A) Tom's work is correct.\newline(B) Tom's work is incorrect. He first made a mistake in Step 11.\newline(C) Tom's work is incorrect. He first made a mistake in Step 22.\newline(D) Tom's work is incorrect. He first made a mistake in Step 33.

Full solution

Q. Tom was asked to determine whether f(x)=x3+x f(x)=x^{3}+x is even, odd, or neither. Here is his work:\newlineStep 11: Find expression for f(x) f(-x) \newlinef(x)=(x)3+x=x3+x \begin{aligned} f(-x) & =(-x)^{3}+x \\ & =-x^{3}+x \end{aligned} \newlineStep 22: Check if f(x) f(-x) is equal to f(x) f(x) or f(x) -f(x) \newlinex3+x -x^{3}+x isn't the same as f(x)=x3+x f(x)=x^{3}+x or f(x)=x3x -f(x)=-x^{3}-x .\newlineStep 33: Conclusion\newlinef(x) f(-x) isn't equivalent to either f(x) f(x) or f(x) -f(x) , so f f is neither even nor odd.\newlineIs Tom's work correct? If not, what is the first step where Tom made a mistake?\newlineChoose 11 answer:\newline(A) Tom's work is correct.\newline(B) Tom's work is incorrect. He first made a mistake in Step 11.\newline(C) Tom's work is incorrect. He first made a mistake in Step 22.\newline(D) Tom's work is incorrect. He first made a mistake in Step 33.
  1. Find f(x)f(-x): Find the expression for f(x)f(-x).f(x)=(x)3+(x)f(-x)=(-x)^{3}+(-x)This should be x3x-x^{3}-x, not x3+x-x^{3}+x as Tom wrote.

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