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Today, the population of Canyon Falls is 22,500 and the population of Swift Creek is 15,200 . The population of Canyon Falls is decreasing at the rate of 740 people each year while the population of Swift Creek is increasing at the rate of 1,500 people each year. Assuming these rates continue into the future, in how many years from today will the population of Swift Creek equal twice the population of Canyon Falls?

Today, the population of Canyon Falls is 2222,500500 and the population of Swift Creek is 1515,200200 . The population of Canyon Falls is decreasing at the rate of 740740 people each year while the population of Swift Creek is increasing at the rate of 11,500500 people each year. Assuming these rates continue into the future, in how many years from today will the population of Swift Creek equal twice the population of Canyon Falls?

Full solution

Q. Today, the population of Canyon Falls is 2222,500500 and the population of Swift Creek is 1515,200200 . The population of Canyon Falls is decreasing at the rate of 740740 people each year while the population of Swift Creek is increasing at the rate of 11,500500 people each year. Assuming these rates continue into the future, in how many years from today will the population of Swift Creek equal twice the population of Canyon Falls?
  1. Set up equation: Let's denote the number of years from today as y y . We need to set up an equation that represents the situation where the population of Swift Creek equals twice the population of Canyon Falls after y y years.\newlineCanyon Falls population after y y years: 22500740y 22500 - 740y \newlineSwift Creek population after y y years: 15200+1500y 15200 + 1500y \newlineThe equation we need to solve is: 15200+1500y=2(22500740y) 15200 + 1500y = 2(22500 - 740y)
  2. Distribute and combine terms: Now, let's distribute the 22 on the right side of the equation:\newline15200+1500y=450001480y 15200 + 1500y = 45000 - 1480y
  3. Solve for y: Next, we'll combine like terms by adding 1480y 1480y to both sides and subtracting 15200 15200 from both sides:\newline1500y+1480y=4500015200 1500y + 1480y = 45000 - 15200 \newline2980y=29800 2980y = 29800
  4. Final population after 1010 years: Now, we'll solve for y y by dividing both sides of the equation by 2980 2980 :\newliney=298002980 y = \frac{29800}{2980} \newliney=10 y = 10
  5. Final population after 1010 years: Now, we'll solve for y y by dividing both sides of the equation by 2980 2980 :\newliney=298002980 y = \frac{29800}{2980} \newliney=10 y = 10 We have found that after 1010 years, the population of Swift Creek will be twice the population of Canyon Falls.

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