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To solve 23x=12\frac{2}{3}x=12 we multiply both sides by 23\frac{2}{3}

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Q. To solve 23x=12\frac{2}{3}x=12 we multiply both sides by 23\frac{2}{3}
  1. Understand and Identify Operation: Understand the equation and identify the operation needed to isolate xx. The equation is 23x=12\frac{2}{3}x = 12, and we want to find the value of xx. To do this, we need to get xx by itself on one side of the equation. This means we need to undo the multiplication of xx by 23\frac{2}{3}. The inverse operation of multiplying by 23\frac{2}{3} is dividing by 23\frac{2}{3}, which is the same as multiplying by the reciprocal, 32\frac{3}{2}.
  2. Multiply by Reciprocal: Multiply both sides of the equation by the reciprocal of 23\frac{2}{3}, which is 32\frac{3}{2}.(32)×(23x)=(32)×12\left(\frac{3}{2}\right) \times \left(\frac{2}{3}x\right) = \left(\frac{3}{2}\right) \times 12
  3. Simplify Left Side: Simplify the left side of the equation by canceling out the 23\frac{2}{3} with its reciprocal 32\frac{3}{2}. The 22 in the numerator of 32\frac{3}{2} cancels with the 22 in the denominator of 23\frac{2}{3}, and the 33 in the denominator of 32\frac{3}{2} cancels with the 33 in the numerator of 23\frac{2}{3}, leaving us with 32\frac{3}{2}00 on the left side. 32\frac{3}{2}11
  4. Perform Multiplication: Perform the multiplication on the right side of the equation.\newlinex=32×12x = \frac{3}{2} \times 12\newlinex=3×6x = 3 \times 6\newlinex=18x = 18

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