AI tutor

Welcome to Bytelearn!

Let’s check out your problem:

$Tisha tried to evaluate an expression. Here is her work: {:[490÷7^(2)*9-2*3],[=490÷49*9-2*3],[=10*9-2*3],[=90-2*3],[=88*3],[=264]:} Is Tisha's work correct? No, Tisha made a mistake going from Step 1 to Step 2. Tisha should have multiplied 49 and 9 before dividing. The order of operations says to multiply before you divide. No, Tisha made a mistake going from Step 3 to Step 4. Tisha should have multiplied 2 and 3 before subtracting. The order of operations says to multiply before you subtract. Yes, Tisha's work is correct.$

Tisha tried to evaluate an expression. Here is her work: $\newline$ $\begin{aligned} & 490 \div 7^{2} \cdot 9-2 \cdot 3 \\ = & 490 \div 49 \cdot 9-2 \cdot 3 \\ = & 10 \cdot 9-2 \cdot 3 \\ = & 90-2 \cdot 3 \\ = & 88 \cdot 3 \\ = & 264 \end{aligned}$ $\newline$ Is Tisha's work correct? $\newline$ No, Tisha made a mistake going from Step $1$ to Step $2$ . Tisha should have multiplied $49$ and $9$ before dividing. The order of operations says to multiply before you divide. $\newline$ No, Tisha made a mistake going from Step $3$ to Step $4$ . Tisha should have multiplied $2$ and $3$ before subtracting. The order of operations says to multiply before you subtract. $\newline$ Yes, Tisha's work is correct.

View step-by-step help

Home

Math Problems

Grade 6

One-step inequalities: word problems

Full solution

Q. Tisha tried to evaluate an expression. Here is her work:

\newline

\begin{aligned} & 490 \div 7^{2} \cdot 9-2 \cdot 3 \\ = & 490 \div 49 \cdot 9-2 \cdot 3 \\ = & 10 \cdot 9-2 \cdot 3 \\ = & 90-2 \cdot 3 \\ = & 88 \cdot 3 \\ = & 264 \end{aligned}

\newline

Is Tisha's work correct?

\newline

No, Tisha made a mistake going from Step

1

to Step

2

. Tisha should have multiplied

49

and

9

before dividing. The order of operations says to multiply before you divide.

\newline

No, Tisha made a mistake going from Step

3

to Step

4

. Tisha should have multiplied

2

and

3

before subtracting. The order of operations says to multiply before you subtract.

\newline

Yes, Tisha's work is correct.

Check Step: Check Tisha's first step: $490 \div 7^{2} \times 9 - 2 \times 3$ . Calculate $7^2 = 49$ .
Calculate Division: Divide $490$ by $49$ , which is $490 \div 49 = 10$ .
Calculate Multiplication: Multiply $10$ by $9$ , which is $10 \times 9 = 90$ .
Calculate Subtraction: Subtract $2 \times 3$ from $90$ , which is $90 - 2 \times 3$ . $\newline$ First, calculate $2 \times 3 = 6$ .
Identify Mistake: Now subtract $6$ from $90$ , which is $90 - 6 = 84$ . Tisha got $88$ instead of $84$ ; there's a mistake here.