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There were 21 students running in a race. How many different arrangements of first, second, and third place are possible?
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There were 2121 students running in a race. How many different arrangements of first, second, and third place are possible?\newlineAnswer:

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Q. There were 2121 students running in a race. How many different arrangements of first, second, and third place are possible?\newlineAnswer:
  1. Permutation Problem: We need to calculate the number of ways to choose the first, second, and third place winners from 2121 students. This is a permutation problem because the order matters.
  2. First Place Selection: For the first place, there are 2121 possible students who could win.
  3. Second Place Selection: After the first place is chosen, there are 2020 students left for the second place.
  4. Third Place Selection: Finally, for the third place, there are 1919 students remaining to choose from.
  5. Total Arrangements Calculation: To find the total number of different arrangements, we multiply the number of choices for each position: 2121 (for first place) ×\times 2020 (for second place) ×\times 1919 (for third place).
  6. Product Calculation: Calculating the product: 21×20×19=798021 \times 20 \times 19 = 7980.

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